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solmaris [256]
4 years ago
12

Give an example of a collision in real life. Use the law of conservation of energy to describe the transfer of momentum. Be sure

and discuss the momentum before and after the collision occurs. You will need at least 3 sentences to thoroughly answer this question.
Physics
1 answer:
ozzi4 years ago
7 0

Explanation :

Using the law of conservation of energy  

When two cars collide with each other then the momentum is same before collision and after collision but energy is changed after collision in form of heat and sound.

We know this collision is inelastic collision.

In Inelastic collision, when two objects collide with each other then the momentum is conserved but kinetic energy is not conserved.  

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How are gravity and air resistance alike? How are they different?​
Iteru [2.4K]
Air resistance is a force that slows down objects moving through the air. ... Objects are affected by gravity the same, but air resistance can affect the speed of an object's descent. An object with more surface area will have more air resistance.
8 0
3 years ago
What sort of element can be found in Group 13 of the periodic table?
frutty [35]

Answer:

Boron group

Explanation:

I googled

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7 0
3 years ago
A boat moves through the water with two forces acting on it. One is a 2000 N forward push by the water on the propeller, and the
jekas [21]

Answer:

a). a=0.2 \frac{m}{s^{2} }

b). x=10m

c). v=2\frac{m}{s}

Explanation:

Force forward push = 2000N

Resistive force due water=1800N

Net force=2000N-1800N

Fn=200N

m=1000kg

t=10sec

a).

F_{n} =m*a\\a=\frac{F_{n}}{m}\\ a=\frac{200N}{1000kg}\\ a=0.2 \frac{m}{s^{2} }

b).

x_{f}=x_{o}+ v_{o}*t+\frac{1}{2}*a*t^{2}\\x_{o}=0\\v_{o}=0\\x_{f}=\frac{1}{2}*a*t^{2}\\x_{f}=\frac{1}{2}*0.2*(10)^{2}  \\x_{f}=10m

c).

v_{f}=v_{o}+a*t\\v_{o}=0\\v_{f}=a*t\\v_{f}=0.2\frac{m}{s^{2} }*10s\\v_{f}=2\frac{m}{s}

3 0
3 years ago
Need help!!
aniked [119]
Without air resistance, the ball would reach a height of h = 31.9 m(pic 1)
The gravitational potential energy difference would be ΔU = 62.588J - 43.164J = 19,424J (pic2 + 3)
The work done by air resistance must be equal to the energy difference(pic4)
The magnitude of the air resistance: F = 0.883N

6 0
3 years ago
When a high-mass main sequence star runs out of both hydrogen and helium in its core, the core begins to fuse
faust18 [17]

Answer:

The core beings to fuse carbon into heavier elements.

Explanation:

As the star runs out of hydrogen and helium, the energy production in the core stops, and there isn't enough outward pressure to hold the star up. The start contracts, and this heats up the core (pressure increases, temperature increases)  creating temperatures high enough to fuse carbon into heavier elements like oxygen, silicon, neon, sulfur, magnesium, and iron.

But a star can sustain itself on Carbon fusion only for so long. In about 600 years (how long exactly depends on the star ) the star runs out of carbon and what happens next depends on the mass of the star; the star either collapses into a neutron star, or begins fusion heavier elements like neon.

7 0
3 years ago
Read 2 more answers
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