(89000/102000)×100
=87.25%
(92000/104000)×100
=88.46%
efficiency is (output/input)×100
if u get confused which way input and output should go, remember the smaller value is always output and it's above in the fraction, then only it's possible to get a efficiency lower than 100.
Answer:
D. Ted expanded more power.
Explanation:
Given the following data;
For Ted.
Force = 10N
Height = 1.5m
Time = 1 seconds
To find Ted's power;
Power = workdone/time
But workdone = force * distance
Workdone = 10 * 1.5
Workdone = 15 Nm
Power = 15/1
Power = 15 Watts.
For Johnny.
Force = 10N
Height = 1.5m
Time = 2 seconds
To find Ted's power;
Power = workdone/time
But workdone = force * distance
Workdone = 10 * 1.5
Workdone = 15 Nm
Power = 15/2
Power = 7.5 Watts
Therefore, from the calculations we can deduce and conclude that Ted expanded more power.
Answer:
E = 3.049 N/C
Explanation:
Induced electric field = e/2 *(pi) *r
Induced electric field = e /(3.14 *19.5) - Eq (1)
e = (pi)r^2*B/t
= 3.14 * (19.5/2*100)^2 * 0.50 T/ 0.1
= 1.867 V
Substituting this value in equation 1, we get –
E = 1.867 V/(3.14 *19.5/100)
E = 3.049 N/C
In a completely inelastic collision, the two objects stick together after the collision.
Answer:
Explanation:
given data:
density of water \rho = 1 gm/cm^3 = 1000 kg/m^3
height of water = 20 cm =0.2 m
Pressure p = 1.01300*10^5 Pa
pressure at bottom
= 1.01300*10^5 - 1000*0.2*9.8
= 99340 Pa
h_[fluid} = 0.307m
