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Anna71 [15]
3 years ago
10

Juan’s classroom is shaped like a rectangle.the room is 40 feet long and 25 feet’s wide which rectangle could be scale drawing o

f Juan’s classroom
Mathematics
1 answer:
Svetach [21]3 years ago
8 0

I think there's an image needed to answer this question?

I tried answering without, but you do need the image.

If the length is 40 and the width is 25, the ration of length:width is 40:25.

This can be simplified to 8:5

So the answer would be any drawing with the following dimensions:

1. length 8 ft and width 5 ft

2. length 16 ft and width 10 ft

3. length 24 ft and width 15 ft

4. length 32 ft and width 20 ft

5. length 40 ft and width 25 ft

It's most likely not the last 3 because the sizes are very big, but yeah a scale drawing maintains the same ratio so I assume one of the options for your answers is gonna be one of the answers from 1 - 4 above (5 is the given dimensions so I highly doubt that's the answer)

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on a lake, Carol rowed a boat for 1/8 mile. Then luke rowed the boat for 3/8 mile. how far did carol and like row in all? simpli
Semmy [17]

Answer:

Total = \frac{1}{2}

Step-by-step explanation:

Given

Carol = \frac{1}{8}

Luke = \frac{3}{8}

Required

How far did they row together

To do this, we simply add the distance they both covered.

Total = Carol + Luke

This gives;

Total = \frac{1}{8} + \frac{3}{8}

Take LCM

Total = \frac{1+3}{8}

Total = \frac{4}{8}

Simplify

Total = \frac{1}{2}

<em>Hence, they both rowed 1/2 mile</em>

7 0
3 years ago
In Circle P, m EA=58, m BC=42, m CD=90, find:
elena55 [62]

Circle theorem states that the angle that an arc subtends at the center of a

circle is twice the angle subtended at the circumference.

The values are as follows;

  1. m∠EDA = <u>90°</u>
  2. m∠BDC = <u>21°</u>
  3. m∠BEC = <u>21°</u>
  4. m\widehat{AB} =<u> 80°</u>
  5. m∠AEB = <u>40°</u>
  6. m∠ECA =  <u>29°</u>
  7. m∠BAC = <u> 21°</u>
  8. <u />m\widehat{ED}  =  <u>90°</u>
  9. m∠ECD = <u>45°</u>
  10. m∠ACB = <u>40°</u>
  11. m∠EBD = <u>45°</u>
  12. m∠ADB = <u>40°</u>
  13. m∠CAD = <u>45°</u>
  14. m∠EAB = <u>90°</u>
  15. m∠EBC = <u>90°</u>

<u />

Reasons:

\displaystyle 1. \ \mathbf{m\angle EDA} = \frac{1}{2} \cdot m\angle EPC Angle subtended at center is twice angle at circumference.

m∠EPC = 180°

∴  m∠EDA = 0.5 × 180° = <u>90°</u>

2. m\widehat{BC} = 42°, therefore, m∠BPC = 42°

\displaystyle \ m\angle BDC= \frac{1}{2} \cdot m\angle BPC

m∠BDC = 0.5 × 42° =<u> 21°</u>

3. m∠BEC = m∠BDC = <u>21°</u>

4. m\widehat{AB} = 180° - (58° + 42°) =<u> 80°</u>

5. \mathbf{m\widehat{AB}} = m∠APB by definition

m∠AEB = 0.5 × m∠APB

m∠AEB = 0.5 × 80° = <u>40°</u>

6. m∠ECA = 0.5 × m∠AE

Therefore;

m∠ECA = 0.5 × m\widehat{EA}

m∠ECA = 0.5 × 58° = 29°

m∠ECA =  <u>29°</u>

7. m∠BAC = 0.5 × \mathbf{m\widehat{BC}}

m∠BAC = 0.5 × 42° = 21°

m∠BAC = <u> 21°</u>

8. m\widehat{ED}  = 180° - \mathbf{m\widehat{CD}}

m\widehat{ED}  = 180° - 90° = 90°

\mathbf{m\widehat{ED}}  =  <u>90°</u>

9. m∠ECD = 0.5 × \mathbf{m\widehat{ED}}

m∠ECD = 0.5 × 90° = <u>45°</u>

10. m∠ACB = 0.5 × m\widehat{AB}

m∠ACB = 0.5 × 80° = <u>40°</u>

11. m∠EBD = 0.5 × \mathbf{m\widehat{ED}}

m∠EBD = 0.5 × 90° = <u>45°</u>

12. m∠ADB = 0.5 × \mathbf{m\widehat{AB}}

m∠ADB = 0.5 × 80° = <u>40°</u>

13. m∠CAD = 0.5 × \mathbf{m\widehat{CD}}

m∠CAD = 0.5 × 90° = <u>45°</u>

14. m∠EAB = 0.5 ×\mathbf{m\widehat{EABC}}

m∠EAB = 0.5 × 180° = <u>90°</u>

15. m∠EBC = 0.5 ×\mathbf{m\widehat{EABC}}

m∠EBC = 0.5 × 180° = <u>90°</u>

<u />

<u />

Learn more about circle theorems here:

brainly.com/question/25101481

3 0
3 years ago
Exploring Triangles and Other Polygons
aleksley [76]
What about it lollsss
6 0
4 years ago
∠A and \angle B∠B are supplementary angles. If m\angle A=(x+6)^{\circ}∠A=(x+6) ∘ and m\angle B=(7x+30)^{\circ}∠B=(7x+30) ∘ , the
nikitadnepr [17]

Answer:

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Step-by-step explanation:

6 0
3 years ago
What is 25/2 in simplest form?
AysviL [449]
Well the answer would be 12.5. I hoped that this helped. :)
5 0
3 years ago
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