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3 years ago

Which subtraction expression

Mathematics

2 answers:

dolphi86 [110]3 years ago

6 0

Answer:

(3 + 5i) – (2 + i)

Step-by-step explanation:

Bond [772]3 years ago

5 0

If you would like to know which subtraction expression has the difference 1 + 4i, you can calculate this using the following steps:

a. (–2 + 6i) – (1 – 2i) = –2 + 6i – 1 + 2i = –3 + 8i

b. (–2 + 6i) – (–1 – 2i) = –2 + 6i + 1 + 2i = –1 + 8i

c. (3 + 5i) – (2 – i) = 3 + 5i – 2 + i = 1 + 6i

d. (3 + 5i) – (2 + i) = 3 + 5i – 2 – i = 1 + 4i

The correct result would be d. (3 + 5i) – (2 + i).

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1. A circular swimming pool has a diameter of 60 feet, and is surrounded by a concrete sidewalk that is 5 feet wide. What is the

Ivenika [448]

We first calculate the area of the entire pool and the side walk.

Given that the pool has a diameter of 60 feet and that the side walk surrounds the pool with a width of 5 feet. This means that the diameter of the entire pool and the side walk is 60 + 5 + 5 = 70 feet and the radius is 70 / 2 = 35 feet

Thus the area of the entire pool and the side walk is obtained as follows:

$Area=\pi r^2 \\ \\ =\pi(35)^2=1,225\pi\ square\ feet$

Given that the pool has a diameter of 60 feet, this means that the radius of the pool is 30 feet.

Thus the area of the pool is given by:

$Area_{pool}=\pi r^2 \\ \\ =\pi(30)^2=900\pi\ square\ feet$

Therefore, the area of the sidewark is the area of the entire pool and side walk minus the area of the pool, this is given by:

$Area_{side walk}=1,225\pi-900\pi \\ \\ =325\pi=1,021 \ square\ feet.$

6 0

3 years ago

Given the functions ƒ(x) and g(x), which of the following statements is true? x -2 -1 0 1 2 ƒ(x) -3 3 5 3 -3 g(x) = -x2 + 4x ƒ(x

Morgarella [4.7K]

Answer:

The correct option is 1.

Step-by-step explanation:

From the given table is notices that the function f(x) is a downward parabola.

The maximum value of f(x) is 5 at x=1.

The function g(x) is

$g(x)=-x^2+4x$

vertex of the parabola is

$(\frac{-b}{2a}, g(\frac{-b}{2a}))$

$(\frac{-4}{2\times 1}, g(\frac{-4}{2\times 1})$

$(2, g(2))$

Put x=2.

$g(x)=-2^2+4(2)=4$

Therefore the vertex of g(x) is (2,4). The vertex of a downward parabola is the maximum point of the function.

Therefore ƒ(x) has the greater maximum. Option 1 is correct.

5 0

3 years ago

A steel safe with mass 2200 kg falls onto concrete. Just

Virty [35]

The kinetic energy of the safe increases the force exerted by the concrete

to several times the weight of the safe.

The magnitude of the force exerted on the safe by the concrete on the is approximately $\underline{29.\overline 3 \, \mathrm{MN}}$

The concrete exerts a force that is approximately 1,359.16 times the weight of the safe.

Reasons:

First part

The mass of the steel safe, m = 2,200 kg

Velocity of the safe just before it hits the concrete, v = 40 m/s

The amount by which the safe was compressed, d = 0.06 m

The kinetic energy, K.E., of the safe just before it hits the round is therefore;

$\displaystyle K.E. = \mathbf{\frac{1}{2} \cdot m \cdot v^2}$

$\displaystyle K.E._{safe} = \frac{1}{2} \times 2,200 \times 40^2 = 1,760,000 \ Joules$

Work done by concrete, W = Force, F × Distance, d

$\displaystyle Force, \, F = \mathbf{\frac{Work, \, W}{Distance, \, d}}$

By the law of conservation of energy, we have;

The work done by the concrete, W = The kinetic energy, K.E. given by the safe

W = K.E. = 1,760,000 J

The effect of the work = The change in the height of the safe

Therefore;

The distance, d, over which the force of the concrete is exerted = The change in the height of the safe = 0.06 m

d = 0.06 m

Therefore;

$\displaystyle The \ force \ of \ the \ concrete, \, F = \frac{1,760,000\, J}{0.06 \, m} = 29,333,333. \overline 3 \, N = 29.\overline 3 \ MN$

The force of the concrete on the safe = $\underline{29.\overline 3 \ MN}$

Second part:

The gravitational force of the Earth on the safe, W = The weight of the safe

W = Mass, m × Acceleration due to gravity, g

W = 2,200 kg × 9.81 m/s² ≈ 21,582 N

The ratio of the force exerted by the concrete to the weight of the safe is found as follows;

$\displaystyle Ratio \ of \ forces = \frac{29.\overline 3 \times 10^6 \, N}{21,582 \, N} = \frac{4,000,000}{2,943} \approx \mathbf{1359.16}$

The force exerted by the concrete is approximately 1,359.16 times the weight of the safe.

Learn more here:

brainly.com/question/21060171

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3 years ago

Amrit initiated new venture with cash rupees 20000 and bank balance rupees 80000 journal entry

ss7ja [257]

Answer:

100000 rupees great success!

Step-by-step explanation:

8 0

3 years ago

Help please all the point will go to the persons with the correct answer !!

amm1812

Answer:

(1,-2)

(1,-6)

(3,-3)

Step-by-step explanation:

8 0

3 years ago