The initial statement is: QS = SU (1)
QR = TU (2)
We have to probe that: RS = ST
Take the expression (1): QS = SU
We multiply both sides by R (QS)R = (SU)R
But (QS)R = S(QR) Then: S(QR) = (SU)R (3)
From the expression (2): QR = TU. Then, substituting it in to expression (3):
S(TU) = (SU)R (4)
But S(TU) = (ST)U and (SU)R = (RS)U
Then, the expression (4) can be re-written as:
(ST)U = (RS)U
Eliminating U from both sides you have: (ST) = (RS) The proof is done.

You then would eliminate 6, by adding 6 to both sides

Then you want all of the X's on the same side, so you subtract 2x from both sides.

Then to isolate the X, you divide by 2

The answer is x=2
Answer:
It looks like there aren't many great matches for your search
Error occurred while trying to find this answer
100<28+12d
If she wants to collect over 100 then the 100 would be less than (<) what she collects. She is starting with 28 so whatever she collects is added on. Because she collects 12 a day, you would multiply 12 by however many days, d, she collects.
Answer:
B
Step-by-step explanation:
Comment
√15 = 3.87
<u>√12 = 3.46 </u> Subtract these 2
Difference = 0.41