Apply the Pyth Thm twice:
diagonal of base is sqrt(4^2+6^2).
Then the length of diagonal AB is L = [sqrt(4^2+6^2)]^2 + [sqrt(1)]^2
Answer:
a) true
Step-by-step explanation:
The bottom-line numbers from synthetic division <em>alternate signs</em>, indicating that -2 is a lower bound. The given statement is true.
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If the signs were all positive, it would indicate the proposed zero is an <em>upper bound</em>.
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A graph shows all real zeros are greater than -2.
Answer:
0.7 = 70%.
Step-by-step explanation:
There are 5 cans, and she will pick 2, so the number of possibilities that she can pick 2 cans is a combination of 5 choose 2:
C(5,2) = 5!(3!*2!) = 5*4/2 = 10
To find how many possibilities there are with at least 1 can of soup, we can find the number of groups that include no cans of soup, and then see how many possibilities complete the total 10:
There are 3 "no-soup" cans, so the number of possibilities is a combination of 3 choose 2:
C(3,2) = 3!/2! = 3
So, there are 3 possibilities that have no cans of soup, so the number of possibilities that have at least 1 can of soup is 10 - 3 = 7
Then, the probability is 7 / 10 = 0.7 = 70%.
Answer:
<em>120°, 120°, 60°, 60°</em>
Step-by-step explanation:
m∠1 = 180° - 60° = 120°
m∠1 = m ∠2 (alternate interior)
m∠3 = 60° (vertical to given angle)
m∠4 = m∠3 (alternate exterior)
The answer is $14 Saul put into his bank accout