Answer:
D
Step-by-step explanation:
Answer:
The x-coordinate of the point changing at ¼cm/s
Step-by-step explanation:
Given
y = √(3 + x³)
Point (1,2)
Increment Rate = dy/dt = 3cm/s
To calculate how fast is the x-coordinate of the point changing at that instant?
First, we calculate dy/dx
if y = √(3 + x³)
dy/dx = 3x²/(2√(3 + x³))
At (x,y) = (1,2)
dy/dx = 3(1)²/(2√(3 + 1³))
dy/dx = 3/2√4
dy/dx = 3/(2*2)
dy/dx = ¾
Then we calculate dx/dt
dx/dt = dy/dt ÷ dy/dx
Where dy/dx = ¾ and dy/dt = 3
dx/dt = ¾ ÷ 3
dx/dt = ¾ * ⅓
dx/dt = ¼cm/s
The x-coordinate of the point changing at ¼cm/s
Answer
50 miles:) I'm positive but there may be a chance it's 200
This is a very long question. I'm not going to write all of it out but I will give you a starting point. Find your x by making y in the formula equal to 0.
2x + 3y = 1470
2x + 3(0) = 1470
2x = 1470
x = 735
Your furthest point on the x axis is (735,0).
Do the same for y.
2x + 3y = 1470.
2(0) + 3y = 1470
3y= 1470
y= 490
Your highest point is (0,490).
Now that both are plotted, draw a straight line connecting the two points. There's your graph.
Check
