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Answer:
6(8x-3)x(3x²-7)
Step-by-step explanation:
144x³-54x²-336x+126
=6(24x³-9x²-56x+21)
=6(3x²x(8x-3)-7(8x-3))
=6(8x-3)x(3x²-7)
Given:
The cost of each carnival ticket is $5.
To find:
The equation, table of values and graph for the given problem.
Solution:
Let x be the number of tickets and y be the total money spent on tickets.
Cost of one ticket = $5
Cost of x tickets = $5x
So, total cost is
The required equation is .
At x=1,
At x=2,
At x=3,
The required table of values is
x y
1 5
2 10
3 15
So, the required table of values is table A.
From the above table, it is clear that the graph passes through the point (1,5), (2,10) and (3,15). The graph B passes through these points.
So, the required graph is graph B.
Since the required answers are , table A, graph B, therefore the correct option is B.
17) f(x) = 16/(13-x).
In order to find domain, we need to set denominator expression equal to 0 and solve for x.
And that would be excluded value of domain.
13-x =0
Adding x on both sides, we get
13-x +x = x.
13=x.
Therefore, domain is All real numbers except 13.
18).f(x) = (x-4)(x+9)/(x^2-1).
In order to find the vertical asymptote, set denominator equal to 0 and solve for x.
x^2 -1 = 0
x^2 -1^2 = 0.
Factoring out
(x-1)(x+1) =0.
x-1=0 and x+1 =0.
x=1 and x=-1.
Therefore, Vertical asymptote would be
x=1 and x=-1
19) f(x) = (7x^2-3x-9)/(2x^2-4x+5)
We have degrees of numberator and denominator are same.
Therefore, Horizontal asymptote is the fraction of leading coefficents.
That is 7/2.
20) f(x)=(x^2+3x-2)/(x-2).
The degree of numerator is 2 and degree of denominator is 1.
2>1.
Degree of numerator > degree of denominator .
Therefore, there would no any Horizontal asymptote.
