The atomic number for U is?

30 POINTS FOR THE GENUIS WHO CAN ANSWER THIS!!

bearhunter [10]

Answer:

Answers are below in bold

Step-by-step explanation:

1) A = 1/2bh Use this equation to find the area of each triangular base

A = 1/2(8)(6) Multiply

A = 1/2(48) Multiply

A = 12cm² Area of each triangular base

2) A = L x W Use this equation to find the area of the bottom rectangular face

A = 20 x 8 Multiply

A = 160 cm² Area of the bottom rectangular face

3) A = L x W Use this equation to find the area of the back rectangular face

A = 20 x 6 Multiply

A = 120 cm² Area of the back rectangular face

4) A = L x W Use this equation to find the area of the sloped rectangular face

A = 20 x 10 Multiply

A = 200 cm² Area of the sloped rectangular face

5) To find the total surface area of the triangular prism, add together all of the numbers.

A = 12 + 12 + 160 + 120 + 200 Add

A = 504 cm² Total area of the triangular prism

6 0

3 years ago

(x-2)^3+13=-112<br> <img src="https://tex.z-dn.net/?f=%28x-2%29%5E3%2B13%3D-112" id="TexFormula1" title="(x-2)^3+13=-112" alt="(

yKpoI14uk [10]

Answer:

x = -3

Step-by-step explanation:

(x - 2)^3 + 13 = -112

Subtract 13 from both sides

(x - 2)^3 = -125

Take the cube root of both sides

x - 2 = -5

Add 2 to both sides

x = -3

7 0

3 years ago

A company claims that the mean weight per apple they ship is 120 grams with a standard deviation of 12 grams. Data generated fro

Veronika [31]

Answer:

There is no sufficient evidence to reject the company's claim at the significance level of 0.05

Step-by-step explanation:

Let $\mu$ be the true mean weight per apple the company ship. We want to test the next hypothesis

$H_{0}:\mu=120$ vs $H_{1}:\mu\neq 120$ (two-tailed test).

Because we have a large sample of size n = 49 apples randomly selected from a shipment, the test statistic is given by

$Z=\frac{\bar{X}-120}{\sigma/\sqrt{n}}$ which is normally distributed. The observed value is

$z_{0}=\frac{122.5-120}{12/\sqrt{49}}=1.4583$ . The rejection region for $\alpha = 0.05$ is given by RR = {z| z < -1.96 or z > 1.96} where the area below -1.96 and under the standard normal density is 0.025; and the area above 1.96 and under the standard normal density is 0.025 as well. Because the observed value 1.4583 does not fall inside the rejection region RR, we fail to reject the null hypothesis.

5 0

3 years ago

PRECALC QUESTION! Convert the polar representation of this complex number into its standard form: z = 2(cos 11pi/6+ i sin 11pi/6

Tanzania [10]

$\bf z=2\left[ cos\left( \frac{11\pi }{6} \right) + i\ sin\left( \frac{11\pi }{6} \right) \right]\qquad 
\begin{cases}
r=2\\
\theta=\frac{11\pi }{6}\\
-----\\
a=x=rcos(\theta)\\
b=y=rsin(\theta)
\end{cases}\implies a+bi
\\\\\\
2cos\left( \frac{11\pi }{6} \right)+2sin\left( \frac{11\pi }{6} \right)\ i\implies 2\cdot \cfrac{\sqrt{3}}{2}+2\cdot \cfrac{-1}{2}\ i\implies \sqrt{3}-1i
\\\\\\
\boxed{\sqrt{3}-i}$

7 0

3 years ago

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The graph below represents c, the amount a phone company charges, based on m, the number of minutes the customer uses each month

Lelechka [254]

The y-intercept of the graph shows that at m = 0, c = 15. We can see a constant slope that causes the graph to pass through m = 20, c = 20, as well as m = 40, c = 25. This shows a constant increase of $5/20 minutes, or a slope of 5/20 = 1/4. Based on slope-intercept form y = mx+b, the equation would be c = (1/4)m+15, from 0 <= m <= 44,640. This is the second of the given choices.

4 0

3 years ago

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