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Anna11 [10]
3 years ago
7

An electrician charges an initial fee of $35 for attending a house call. Thereafter, he charges $15 for every hour spent on the

job. The equation for this is represented = 35 + 15, where $Y represents the charges the house owner has to pay and is the number of hours the electrician spends on the job: (a) , find the amount of money the house owner needs to pay if he spends (i) 1 hour (ii) 2 hours (iii) 3 hours (iv) 4 hours on the job very urgent
Mathematics
1 answer:
umka21 [38]3 years ago
3 0

Answer:

1 hour=35+15=50

2 hours=35+15(2)=65

3 hours=35+15(3)=80

4 hours=35+15(4)=95

Step-by-step explanation:

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Given that a/b = 3/5 and b/c = 4/5<br> Find a:b:c
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Answer:

12:20:25

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2 years ago
A train to New York city leaves a station every 7 minutes. Another train to Boston leaves the station every 6 minutes. Suppose i
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Answer:

7:12 a.m

Step-by-step explanation:

Given that:

Train to New York city leaves station every 7 minutes

Train to Boston leaves station every 6 minutes

Current time = 6:30 a.m

Time both will leave station together is obtained by finding the least common multiple of 6 and 7

Multiples of ;

6 = 6, 12, 18, 24, 30, 36, 42, 48, 54, 60,...

7 = 7, 14, 21, 28, 35, 42, 49, 56, 63, 70,...

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7 0
3 years ago
What is (7z-5)-(3x-2) equivalent to ?
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Answer:

7z -3x -3 is the solution to the equation

Step-by-step explanation:

7z -5 -3x +2

7z -3x -5+2

7z -3x -3

6 0
3 years ago
Paula Purchaser borrowed $500 at 12 percent for one year. She paid a $25 processing fee. The interest paid will be $ . Thus, the
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4 0
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liubo4ka [24]

Answer:

Step-by-step explanation:

\displaystyle\  \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\frac{0}{0} \\\\we\ can \ use\ Hospital's\ Rule\\\\\\f(x)=\sqrt{2x}-\sqrt{3x-a}  \qquad  f'(x)=\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} \\\\g(x)=\sqrt{x} -\sqrt{a}  \qquad g'(x)=\dfrac{1}{2\sqrt{x}} \\\\\\\displaystyle\  \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\lim_{n \to a} \dfrac{\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}}  }{\dfrac{1}{2\sqrt{x}} }\\\\

\displaystyle \lim_{n \to a} \dfrac{2\sqrt{x} }{\sqrt{2x}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}  =\lim_{n \to a} \dfrac{2 }{\sqrt{2}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3*\sqrt{a} }{\sqrt{2a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3}{\sqrt{2}}\\\\\\=-\ \dfrac{1}{\sqrt{2}}\\\\

7 0
3 years ago
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