Please assist me with the missing answers. Scores on the final exam in Ms. Meyer's statistics class follow a normal distribution
1 answer:
Answer: Ron's z-score is <u>+1.2</u>.
B. 1.2 standard deviation above the mean .
Step-by-step explanation:
Let X deontes the scores of the final exam
Given : Ms. Meyer's statistics class follow a normal distribution with Mean = 82
standard deviation =5.1
Formula :
Ron scored 88 on the final.
So, put x=88
Ron's z-score is <u>+1.2</u>.
Also, 88= 86+(1.2 x 5.1) = Mean +1.2 x (standard deviation)
i.e. This means that Ron's final score is<u> 1.2 standard deviation above the mean </u>.
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