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3 years ago

Solve for x. (x - 5)(x - 5) = 0

Mathematics

1 answer:

OverLord2011 [107]3 years ago

6 0

Answer:

x=5

Step-by-step explanation:

(x - 5)(x - 5) = 0

x-5=0

x=5

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A 100 gallon tank initially contains 100 gallons of sugar water at a concentration of 0.25 pounds of sugar per gallon suppose th

Vsevolod [243]

At the start, the tank contains

(0.25 lb/gal) * (100 gal) = 25 lb

of sugar. Let $S(t)$ be the amount of sugar in the tank at time $t$ . Then $S(0)=25$ .

Sugar is added to the tank at a rate of P lb/min, and removed at a rate of

$\left(1\frac{\rm gal}{\rm min}\right)\left(\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm gal}\right)=\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm min}$

and so the amount of sugar in the tank changes at a net rate according to the separable differential equation,

$\dfrac{\mathrm dS}{\mathrm dt}=P-\dfrac S{100}$

Separate variables, integrate, and solve for S.

$\dfrac{\mathrm dS}{P-\frac S{100}}=\mathrm dt$

$\displaystyle\int\dfrac{\mathrm dS}{P-\frac S{100}}=\int\mathrm dt$

$-100\ln\left|P-\dfrac S{100}\right|=t+C$

$\ln\left|P-\dfrac S{100}\right|=-100t-100C=C-100t$

$P-\dfrac S{100}=e^{C-100t}=e^Ce^{-100t}=Ce^{-100t}$

$\dfrac S{100}=P-Ce^{-100t}$

$S(t)=100P-100Ce^{-100t}=100P-Ce^{-100t}$

Use the initial value to solve for C :

$S(0)=25\implies 25=100P-C\implies C=100P-25$

$\implies S(t)=100P-(100P-25)e^{-100t}$

The solution is being drained at a constant rate of 1 gal/min; there will be 5 gal of solution remaining after time

$1000\,\mathrm{gal}+\left(-1\dfrac{\rm gal}{\rm min}\right)t=5\,\mathrm{gal}\implies t=995\,\mathrm{min}$

has passed. At this time, we want the tank to contain

(0.5 lb/gal) * (5 gal) = 2.5 lb

of sugar, so we pick P such that

$S(995)=100P-(100P-25)e^{-99,500}=2.5\implies\boxed{P\approx0.025}$

5 0

3 years ago

4х – 9у – 2 = 0 12х - 5у + 38 = 0 answer in x and y intercept

garri49 [273]

Answer:

x=5

y=2

Step-by-step explanation:

-3(4х – 9у – 2 = 0)

=-12x+27y+6

12х - 5у + 38

-12x+27y+6

22y=44

y=2

4x-9(2)-2=

=4x-20

4x=20

x=5

3 0

3 years ago

Jina must choose a number between 55 and 101 that is a multiple of 3, 6, and 9. Write all the numbers that she could choose.

kupik [55]

Answer:

Join Zoom Meeting

Meeting ID: 385 546 8984

Passcode: icecream4

Step-by-step explanation:

8 0

3 years ago

How do you find the y-intercept and the slope for number 11

Sophie [7]

The first step is to find the slope. Use the slope formula

m = (y2-y1)/(x2-x1)

The two points are (x1,y1) = (-1,5) and (x2,y2) = (2,-1)

So,
x1 = -1
y1 = 5
and
x2 = 2
y2 = -1
will be plugged into the slope formula to get...
m = (y2-y1)/(x2-x1)
m = (-1-5)/(2-(-1))
m = (-1-5)/(2+1)
m = (-6)/(3)
m = -2

The slope is -2

Use m = -2 and one of the points to find the y intercept b. I'll use the point (x,y) = (-1,5) ---> x = -1, y = 5

y = mx+b ... slope intercept form
5 = -2*(-1)+b
5 = 2+b
5-2 = 2+b-2
3 = b
b = 3

The y intercept is 3

-----------------------------------

m = -2 is the slope
b = 3 is the y intercept

Therefore y = mx+b turns into y = -2x+3 as the equation that goes through the two points

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3 years ago

Explain how to decide whether to use graphing, substitution, or elimination to solve a system of equations.

Bess [88]

It depends on the systems of equations. I would stay away from elimination, go for substitution and graph only if asked.

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3 years ago