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3 years ago

Solve -8 = 2y – 2. Show your work and how to check your solution.

Mathematics

1 answer:

Mashcka [7]3 years ago

4 0

Answer: y = -3

Explanation:

-8 = 2y - 2
-2y = -2 + 8
y = 6/-2
y = -3

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8x - 2y =48 y=4 what does x =

pshichka [43]

x is equal to 7, you plug in the 4 as the y

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3 years ago

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Find slope of the line passing through the points (-6,4) and (4,4)

stealth61 [152]

Answer:

Step-by-step explanation:

(y2-y1)/(x2-x1)= slope

(4-4)/(4-(-6)) = 0

7 0

3 years ago

I need help ASAP!!!!!!!!

4vir4ik [10]

Answer:

Step-by-step explanation:

1st rectangle has an area of: h - horizontal sections * l - lateral sections.

A1 = 10 * 10 = 100 units squared

But only a fraction of them are colored.

72 / 100 are colored in the 1st rectangle.

The second has an area of: A2 = 10 * 1 = 10 units squared, but one row in the 2nd rectangle is the same as 10 units in the 1st so the area is still 100 units squared.

But the colored sections are 2/10 or 20/ 100.

Now we subtract 72/100 - 20/100 = 52/100 = 26/50 = 13/25 = 0.52 A

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3 years ago

Find the cdf F(x) associated with each of the following probability density functions. Sketch the graphs of f(x) and F(x).

wolverine [178]

Answer:

See steps below

Step-by-step explanation:

$\bf f(x)=3(1-x)^2\;(0$

$\bf F(x)=\int_{0}^{x}f(t)dt=\int_{0}^{x}3(1-t)^2dt=3\int_{0}^{x}(1-t)^2=1-(1-x)^3$

The cdf associated with f is

$\bf \boxed{F(x)=1-(1-x)^3}$ for 0<x<1

<h3>See picture 1 </h3>

The median is a point x such that

F(x) = ½

so, the median is

$\bf 1-(1-x)^3=1/2\rightarrow (1-x)^3=1/2\rightarrow \boxed{x=1-\sqrt[3]{2}}$

The 25th percentile equals the 1st quartile and is a point x such

F(x) = ¼

and the 25th percentile is

$\bf 1-(1-x)^3=1/4\rightarrow (1-x)^3=3/4\rightarrow \boxed{x=1-\sqrt[3]{3/4}}$

$\bf f(x)=\frac{1}{x^2}\;(1$

$\bf F(x)=\int_{1}^{x}f(t)dt=\int_{1}^{x}\frac{dt}{t^2}=1-\frac{1}{x}$

The cdf associated with f is

$\bf \boxed{F(x)=1-\frac{1}{x}}$ for x>1

<h3>See picture 2 </h3>

The median is

$\bf 1-\frac{1}{x}=\frac{1}{2}\rightarrow \boxed{x=2}$

The 25th percentile is

$\bf 1-\frac{1}{x}=\frac{1}{4}\rightarrow \boxed{x=4/3}$

f(x) = 1/3 for 0<x<1 or 2<x<4

$\bf F(x)=\int_{0}^{x}\frac{dt}{3}=\frac{x}{3}\;(0$

$\bf F(x)=\frac{1}{3}+\int_{2}^{x}\frac{dt}{3}=\frac{1}{3}+\frac{x-2}{3}=\frac{x-1}{3}\;(2$

The cdf associated with f is

$\bf F(x)=\frac{x}{3}$ for 0<x<1

$\bf F(x)=\frac{x-1}{3}$ for 2<x<4

<h3>See picture 3 </h3>

The median is

$\bf \frac{x-1}{3}=1/2\rightarrow x=1+3/2\rightarrow \boxed{x=5/2}$

The 25th percentile is

$\bf \frac{x}{3}=1/4\rightarrow \boxed{x=3/4}$

4 0

4 years ago

The length of a rectangle is 18 cm and the width is 6 cm. A similar rectangle has a width of 2 cm.What is the length of the seco

Novay_Z [31]

Answer:

Length = 6cm

Step-by-step explanation:

You would get 6cm as the length, because 6 ÷ 3 = 2, that is your width. So in the same way, you would divide 18 by 3 and get 6, thus the length of the second rectangle is 6 centimeters

Hope it helps :D

7 0

3 years ago

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