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3 years ago

How long does it take to become an orthodontist?

1 answer:

7 0

Https://www.careervillage.org/questions/9768/how-many-years-does-it-take-to-become-an-orthodontist

I hope this helps you. :)

You might be interested in

Name all the segments that is parallel to the given segment.

Leni [432]

Answer and Step-by-step explanation:

AB is parallel to FE

CA is parallel to EG

CB is parallel to FG

#teamtrees #WAP (Water And Plant)

5 0

3 years ago

Read 2 more answers

What does this symbol mean?

sammy [17]

It means approximately equal to.

4 0

3 years ago

Read 2 more answers

Is this linear relationship a direct variation?

Talja [164]

Since the ratio of of second variable to the ratio of first variable remains constant i.e y/x =8 so, the linear relationship is direct variation.

Step-by-step explanation:

A relationship is said to have direct variation if ratio of second variable to the ratio of first variable remains constant.

A relationship is direct variation if $y=kx\,\,or\,\, \frac{y}{x} =k$ where k is the constant.

Now checking if the given data is having direct variation or not.

x y

3 24

4 32

5 40

6 48

Now finding y/x

if y=24 and x = 3 then y/x = 24/3 = 8

if y=32 and x = 4 then y/x =32/4=8

if y=40 and x = 5 then y/x =40/5 =8

if y=48 and x = 6 then y/x =48/6= 8

Since the ratio of of second variable to the ratio of first variable remains constant i.e y/x =8 so, the linear relationship is direct variation.

Keywords: Direct Variation

Learn more about Direct Variation at:

#learnwithBrainly

5 0

3 years ago

Solve the Anti derivative.

Alex Ar [27]

Answer:

$\displaystyle \int {\frac{1}{9x^2+4}} \, dx = \frac{1}{6}arctan(\frac{3x}{2}) + C$

General Formulas and Concepts:

Algebra I

Factoring

Calculus

Antiderivatives - integrals/Integration

Integration Constant C

U-Substitution

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Trig Integration: $\displaystyle \int {\frac{du}{a^2 + u^2}} = \frac{1}{a}arctan(\frac{u}{a}) + C$

Step-by-step explanation:

Step 1: Define

$\displaystyle \int {\frac{1}{9x^2 + 4}} \, dx$

Step 2: Integrate Pt. 1

[Integral] Factor fraction denominator: $\displaystyle \int {\frac{1}{9(x^2 + \frac{4}{9})}} \, dx$
[Integral] Integration Property - Multiplied Constant: $\displaystyle \frac{1}{9} \int {\frac{1}{x^2 + \frac{4}{9}}} \, dx$

Step 3: Identify Variables

Set up u-substitution for the arctan trig integration.

$\displaystyle u = x \\ a = \frac{2}{3} \\ du = dx$

Step 4: Integrate Pt. 2

[Integral] Substitute u-du: $\displaystyle \frac{1}{9} \int {\frac{1}{u^2 + (\frac{2}{3})^2} \, du$
[Integral] Trig Integration: $\displaystyle \frac{1}{9}[\frac{1}{\frac{2}{3}}arctan(\frac{u}{\frac{2}{3}})] + C$
[Integral] Simplify: $\displaystyle \frac{1}{9}[\frac{3}{2}arctan(\frac{3u}{2})] + C$
[integral] Multiply: $\displaystyle \frac{1}{6}arctan(\frac{3u}{2}) + C$
[Integral] Back-Substitute: $\displaystyle \frac{1}{6}arctan(\frac{3x}{2}) + C$