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qwelly [4]
4 years ago
15

What number must be added to the expression below to complete the square

Mathematics
1 answer:
EastWind [94]4 years ago
3 0

Where is it? In order to help you I need to see what the problem is.



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Write the slope-intercept form of the equation of each line
navik [9.2K]

Answer: y= 3x-1

Step-by-step explanation:

Equation of a straight line:

y = mx + b ------(i)

Step by Step Solution:

Step 1: Calculating Slope (m).

m =

y2-y1

x2-x1

m =

2--1

1-0

m =

3

1

m = 3

Now putting value of m in equation (i)

y = 3x + b -----(ii)

Step 2: Calculating Y-intercept (b).

Lets choose the first point, (0,-1) for calculating y-intercept:

y = mx + b

-1 = 3(0) + b

-1 = 0 + b

-1 = b

b = -1

8 0
2 years ago
Read 2 more answers
#5 A pair of jeans was 30% off the
just olya [345]

Answer:

80

Step-by-step explanation:

8 0
4 years ago
The points ????(0,0), ????(−4,1), ????(−3,5), and ????(1,4) are the vertices of parallelogram OABC Is this parallelogram a
gavmur [86]

Answer:

Yes, parallelogram OABC is a rectangle.

Step-by-step explanation:

The vertices of a parallelogram are O(0,0), A(-4,1), B(-3,5) and C(1,4).

A parallelogram is a rectangle if its any two adjacent sides are perpendicular to each other.

product of slopes of two perpendicular lines is -1.

Formula for slope is

Slope=\dfrac{y_2-y_1}{x_2-x_1}

Using the formula we get

m_{OA}=\dfrac{1-0}{-4-0}=-\dfrac{1}{4}

m_{AB}=\dfrac{5-1}{-3-(-4)}=-\dfrac{4}{1}=4

m_{OA}\times m_{AB}=-\dfrac{1}{4}\times 4=-1

It means OA is perpendicular to AB.

Since two adjacent sides are perpendicular, therefore the given parallelogram OABC is a rectangle.

6 0
4 years ago
Can someone please help me with this
gavmur [86]
A. The reduction in Angela’s tips are cause by low restaurant sales. Even tho shes still getting her 20% it’s less money due to the fact they’re less customers
7 0
3 years ago
Read 2 more answers
the set $s = \$ contains the first $50$ positive integers. after the multiples of 2 and the multiples of 3 are removed, how many
Sophie [7]

Clearly, |S| = 50.

Count the multiples of 2 between 1 and 50:

⌊50/2⌋ = ⌊25⌋ = 25

(where ⌊x⌋ denotes the "floor of x", or the largest integer that is smaller than or equal to x; in other words, round <u>down</u> to the nearest integer)

Count the multiples of 3 between 1 and 50:

⌊50/3⌋ ≈ ⌊16.667⌋ = 16

Since LCM(2, 3) = 6, the sets of multiples of 2 and multiples of 3 have some overlap. Count the multiples of 6 between 1 and 50:

⌊50/6⌋ ≈ ⌊8.333⌋ = 8

Then by the inclusion/exclusion principle, we remove from S

25 + 16 - 8 = 33

elements, so that the new set S contains 50 - 33 = 17 elements.

5 0
3 years ago
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