Question

A man on the fifth floor of a building shouts down to a person on the street. If the angle of elevation from the street to the man in the building is 35° and the man in the building is 40 feet up, about how far away from the building is the person on the street?

Answer 1

The answer is about 57 feet.

Answer 2

Answer: 57 feet

Step-by-step explanation:

Given: The angle of elevation from the street to the man in the building=$35^{\circ}$

If the man in the building is 40 feet up.

From the given , we make a diagram in which $\triangle {ABC}$ is a right triangle, such that

Let AB=40 feet

Then $\tan{35^{\circ}}=\frac{AB}{BC}$

$\\\Rightarrow0.70=\frac{40}{BC}\\\\\Rightarrow\ BC=\frac{BC}{0.70}=57.142\approx57\ feet$

Hence, the distance of the person on the street  from the building is 57 feet