Approximate solutions are
X subset 2 is approximately equal to -2.72
X subset 1 is approximately equal to -0.28
There are 600 students including the seventh and eighth graders at the party.
This problem uses the concept of percentages to define the conditions that are laid in front of us.
Let the original number of students be S , and the number of seventh graders be = 0.60S
We know that percent is used to convey the mathematical term of a fraction multiplied by 100.
Total students after 20 eighth graders arrive = S + 20
And we have that
Number of seventh graders / total number of students = 58%
.60S / [ S + 20 ] = .58 we multiply both sides by S + 20
0.60S =0 .58 [ S + 20]
.60S = .58S + 11.6 we subtract 0.58S from both the sides
0.02S = 11.6 we divide both the sides by .02
S = 11/6 / 0.02 = 580
So the total number of students = 580 + 20 = 600 .
Hence there are 600 students at the party at that time.
To learn more about students visit:
brainly.com/question/17332524
#SPJ1
The answer is 2 hopefully this helped
Answer:
6x ( 3x +4)
X =0 and x = 4/3 or x = 1 1/3
Step-by-step explanation:
Take the common factors out,
Here x is common to both equation and also 6 is common to both equation
So,
6x ( 3x + 4) = 0
So it can be solved by
X = 0 and x = 4/3
Answer:
I think the answer is y = 3x + 12.
Step-by-step explanation:
y = 3 (x - 1) (x - 4)
y = 3x -3 (x - 4)
y = 3x + 12
