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Luba_88 [7]
3 years ago
8

Prachi was 555 kilometers east of her home when she began driving farther east at 707070 kilometers per hour. Let f(n)f(n)f, lef

t parenthesis, n, right parenthesis be Prachi's distance from her home at the beginning of the n^\text{th}n th n, start superscript, start text, t, h, end text, end superscript hour of her drive.
Mathematics
1 answer:
vladimir2022 [97]3 years ago
3 0

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Whenever she began to drive farther east, at 70 km per hour, Prachi was 5 km east of her home.

Let f(n) at the beginning of her nth hour drive be Prachi's distance to her home.

f is a sequence of arithmetic.

Write a series explicit form.

\to f(n) = 70n + 5

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Micheal's mean score for five tests was 82. if four of those tests were 83,75,93, and 67, what was the fifth score on his test?
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The fifth score was 92.

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One of the ways I like to work problems like these is to add the differences from the mean. Those are ...

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Read 2 more answers
Amanda's school is due west of her house and due south of her friend Shereen's house. The distance between the school and Sheree
Blizzard [7]

The Amanda's house is 6.7 km far from her school.

<u>Step-by-step explanation:</u>

From the given information,

  • The Amanda's school is due west of her house forms the base.
  • The school is due south of the Shereen's house forms the height.
  • The straight-line distance between Amanda's house and Shereen's house forms the hypotenuse.

Therefore, It can be determined that it forms the right angle triangle.

It is given that,

The distance between the school and Shereen's house is 2 kilometers.

That is, the height of the triangle = 2 km

The straight-line distance between Amanda's house and Shereen's house is 7 kilometers.

That is, the hypotenuse of the triangle = 7 km

Now, the distance between the Amanda's house and her school is the base of the triangle.

<u>To find the base :</u>

Base = \sqrt{(hypotenuse)^{2}-(height)^{2}  }

⇒ \sqrt{(7)^{2} -(2)^{2} }

⇒ \sqrt{49-4}

⇒ \sqrt{45}

⇒ 6.7 km

Therefore, the Amanda's house is 6.7 km far from her school.

3 0
3 years ago
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