Question

Plz answer this question...

Answer 1

Hello,

1) draw [AB]

2) draw mes (BAB')=78° (|AB|=|AB'| (distance))
draw the circle center B' passant by A.
3)C=middle [BB']

4) draw the half circle with [BB'] as diameter.

5) Intesection of cercle =>D

explain: any right triangle is inscribed in a semicircle

Rem: 78+90=168 and 360-168=192