Question

write an equation for the line with a slope of 3/2 that passes through (4,-2) (I need the answer asap)

Answer 1

The equation of the line that has a slope m is

$y=mx+b.$

Since $m=\dfrac{3}{2},$ the equation is

$y=\dfrac{3}{2}x+b.$

This line passes through the point (4,-2), then the coordinates of this point satisfy the equation:

$-2=\dfra{3}{2}\cdot 4+b,\\ \\-2=6+b,\\ \\b=-8.$

Answer: $y=\dfrac{3}{2}x-8.$