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rosijanka [135]
2 years ago
7

How do i solve this?

Mathematics
1 answer:
Hunter-Best [27]2 years ago
4 0

Step-by-step explanation:

You need to solve for x.

You can do that by either setting both of the equations equal to each other. or Solve each one separately and subtract the EG equation from the EW to get GW

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Write your question here keep it simple and clear
igor_vitrenko [27]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

12 + 12 + 18 + 18 = 60

The perimeter is 60 cm

Have A Nice Day ❤    

Stay Brainly! ヅ    

- Ally ✧    

。☆✼★ ━━━━━━━━━━━━━━  ☾

7 0
2 years ago
Dr. Potter provides vaccinations against polio and measles. Each polio vaccination consists of 444 doses, and each measles vacci
nataly862011 [7]

Answer:

37 polio vaccinations and 23 measles vaccination.

Step-by-step explanation:

Let the number of polio vaccination given=x

Let the number of measles vaccination given=y

Dr. Potter gave a total of 60 vaccinations

x+y=60

Since each polio vaccination consists of 4 doses, and each measles vaccination consists of 2 doses. A total of 184 doses was given out.

4x+2y=184

To find the values of x and y, we solve the two equations simultaneously.

x+y=60             (1)

4x+2y=184        (2)

From (1), x=60-y

Substitute x=60-y into equation 2.

4x+2y=184

4(60-y)+2y=184

240-4y+2y=184

240-184=4y-2y

56=2y

Divode both sides by 2

y=23

Recall earlier that x=60-y

x=60-23=37

Dr Potter gave 37 polio vaccinations and 23 measles vaccination.

6 0
3 years ago
Using the given points, determine the slope. <br><br> (0, 32) and (100, 212)
Allushta [10]
Hi!

To find the slope of two given points, subtract the y values, and subtract the x values, or..

\frac{(y2 - y1)}{(x2 - x1)}

\frac{(212 - 32)}{(100 - 0)}

\frac{180}{100}

The answer is 9/5 or 1.8.

Hope this helps! :)
8 0
2 years ago
Read 2 more answers
The two-way table shows the number of students in a school who like reading and/or gardening.
lisov135 [29]

hello i just took the test the answer is 26

5 0
3 years ago
A researcher believes that the mean weight of competitive runners is about 140 pounds. A sample of 24 elite distance runners has
ExtremeBDS [4]

Answer:

t=\frac{136-140}{\frac{11}{\sqrt{24}}}=-1.781    

p_v =P(t_{(23)}  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is less than 140 pounds at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=136 represent the sample mean

s=11 represent the sample standard deviation

n=24 sample size  

\mu_o =140 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is less than 140, the system of hypothesis would be:  

Null hypothesis:\mu \geq 140  

Alternative hypothesis:\mu < 140  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{136-140}{\frac{11}{\sqrt{24}}}=-1.781    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=24-1=23  

Since is a one left tailed test the p value would be:  

p_v =P(t_{(23)}  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is less than 140 pounds at 5% of signficance.  

4 0
2 years ago
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