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mihalych1998 [28]
3 years ago
7

9. A bag contains 40 slips of paper, numbered 1-40. If one slip is chosen at random, what is the

Mathematics
1 answer:
valina [46]3 years ago
5 0

Answer:

The probability is 0.9

Step-by-step explanation:

Suppose that we have a bag with N outcomes (such that these N outcomes have the same probability of being randomly drawn from the bag, we can suppose that the outcomes are given elements, like marbles or something like that.)

Suppose now that there are K of these elements with a given property.

The probability of randomly drawn one of these K elements is equal to the quotient between the number of these elements in the set (K) and the total number of elements in the bag (N)

The probability is: P = K/N

In this case, we know that there are 40 slips of paper, numbered from 1 to 40.

We want to find the probability of NOT choosing a multiple of 10.

The multiples of 10 in that range are:

10*1 = 10

10*2 = 20

10*3 = 30

10*4 = 40

So we have 4 multiples of 10, then we have 36 non-multiples of 10.

The probability of drawing at random a number that is not a multiple of 10, is equal to the quotient between the number of slips of papers with numbers that are not multiples of 10 (36) and the total number of slips of paper (40)

P = 36/40 = 0.9

The probability is 0.9

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lilavasa [31]
We have the following function:
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 We note that the function depends on x because it is f (x).
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 Therefore we can assume that the function is constant, since:
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The function is zero degree.
7 0
3 years ago
Studies show that a typical giant hummingbird can flap its wings once in 0.08 of a second.
Licemer1 [7]

Answer:

a. 90

b. 360

Step-by-step explanation:

The time taken by humming bird to flap its wings= 0.08 sec

by flying 7.2 seconds a typical giant hummingbird flap its wings \frac{7.2}{0.08} times

= 90 times

Since, A ruby-throated hummingbird can flap its wings 4 times faster than a giant hummingbird, it will flap its wings in every 0.02 sec

so in 7.2 seconds it will flap \frac{7.2}{0.02} times = 360 times

4 0
3 years ago
Bo
Elenna [48]
If you use the scientific notation to simplify these bigger numbers it will make it easier
7 0
3 years ago
Help with 1-9 , please!!!!
murzikaleks [220]
1. 160
You just add normally.
2. -86
3. 89
4. 7
5. -44
6. -14
7. -48
8. 50
9. 70
If you are struggling you can use a website called ixl it cost money but it can really help a lot !
4 0
3 years ago
Read 2 more answers
8. There are 10 balls in a bag numbered from 1 to 10. Three balls are selected at random without replacement.
PIT_PIT [208]

Answer:

a. 720

b. 0.3

Step-by-step explanation:

a.

Three balls are selected at random without replacement.

First ball can be selected in 10 ways

Second ball can be selected in 9 ways

Third ball can be selected in 8 ways

Thus, there are 10×9×8 =720 different ways of selecting three balls.

b.

There are three cases that satisfy this condition

  1. first ball picked is 5, the others are not
  2. first ball is not 5, second is 5, third is not
  3. first and second ball is not five, third ball is 5

Each probabilities are:

  1. \frac{1}{10} * \frac{9}{9} *\frac{8}{8} =\frac{1}{10}
  2. \frac{9}{10} *\frac{1}{9} *\frac{8}{8} =\frac{1}{10}
  3. \frac{9}{10} *\frac{8}{9} *\frac{1}{8} =\frac{1}{10}

Thus, one of the balls selected is the number 5 is then \frac{1}{10} + \frac{1}{10} + \frac{1}{10} = \frac{3}{10}

5 0
3 years ago
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