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Karo-lina-s [1.5K]
4 years ago
8

What is 3m*(2m)^2 +3(2m)^3 ?

Mathematics
1 answer:
Andre45 [30]4 years ago
6 0
(2m)^2 = 4m^2
(2m)^3 = 8m^3

12m^3 + 24m^3 = 36m^3
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The lesser of two consecutive even integers is 10 more than one-half the greater. Find the integers.
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n=\dfrac{1}{2}(n+1)+10\\
2n=n+1+20\\
n=21\\
n+1=22

21 and 22
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3 years ago
sam and jesse each wash 5 cars an hour. they both work for 7 hours over 2 days. how many cars did Sam and Jesse wash?
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Just do how many minutes are in a hour and do that for 2days but 24 times two
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3 years ago
Integrate sin 3x+2x with respect to x plss step-by step ​
Gnoma [55]

Step-by-step explanation:

∫ (sin(3x) + 2x) dx

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3 0
3 years ago
Joan poured 7/8 liter of water into a bottle. It filled 5/6 of the bottle.How many liters of water will completely fill the bott
stepan [7]
Let's set up some equations.

We know that 7/8 of a liter fills up our bottle 5/6 of the way. Thus 7/8=5/6 * b.

Now, let's divide both sides by 5/6 to get b = 21/20. However, none of the answer choices provided are correct. Let's look at each one to determine why it's not correct.

A. This answer is false because 35/48 < 7/8. If 7/8 of a liter doesn't completely fill up the bottle, there is no way that a value less than 7/8 can fill up the bottle - it's impossible.

B. Same case as answer A, but 11/38 instead of 35/48.

C. Same case as answer A, but 11/20 instead of 35/48.

D. This answer however is more than 35/48, so is it correct? No. 113/35 is just over 3. Since 7/8 of a liter almost fills the bottle but does not quite completely fill it, there is no way that adding 2 more liters can fill up the bottle just the tiny 1/6 of the way. That is disproportional and is thus wrong.
6 0
3 years ago
Statistics Probability
andriy [413]

Answer:

Explained below.

Step-by-step explanation:

Denote the variable as follows:

M = male student

F = female student

Y = ate breakfast

N = did not ate breakfast

(a)

Compute the probability that a randomly selected student ate breakfast as follows:

P(Y)=\frac{n(Y)}{N}\\\\=\frac{198}{330}\\\\=0.60

(b)

Compute the probability that a randomly selected student is female and ate breakfast as follows:

P(F\cap Y)=\frac{n(F\cap Y)}{N}\\\\=\frac{121}{330}\\\\=0.367

(c)

Compute the probability a randomly selected student is male, given that the student ate breakfast as follows:

P(M|Y)=\frac{n(M\cap Y)}{n(Y)}\\\\=\frac{77}{198}\\\\=0.389

(d)

Compute the probability that a randomly selected student ate breakfast, given that the student is male as follows:

P(Y|M)=\frac{n(Y\cap M)}{n(M)}\\\\=\frac{77}{154}\\\\=0.50

(e)

Compute probability of the student selected "is male" or "did not eat breakfast" as follows:

P(M\cup N)=P(M)+P(N)-P(M\cap N)\\\\=\frac{n(M)}{N}+\frac{n(N)}{N}-\frac{n(M\cap N)}{N}\\\\=\frac{n(M)-n(N)-n(M\cap N)}{N}\\\\=\frac{154+132-77}{330}\\\\=0.633

(f)

Compute the probability of "is male and did not eat breakfast as follows:

P(M\cap N)=\frac{n(M\cap N)}{N}\\\\=\frac{77}{330}\\\\=0.233

4 0
3 years ago
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