The vertices of a square are its endpoints
The coordinates of the other pairs are: (-1, 3), (4, 3) and (-1, -7), (4, -7)
The given parameters are:
![\mathbf{E = (-1,-2)}](https://tex.z-dn.net/?f=%5Cmathbf%7BE%20%3D%20%28-1%2C-2%29%7D)
![\mathbf{F = (4,-2)}](https://tex.z-dn.net/?f=%5Cmathbf%7BF%20%3D%20%284%2C-2%29%7D)
Calculate the distance EF
![\mathbf{EF = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}](https://tex.z-dn.net/?f=%5Cmathbf%7BEF%20%3D%20%5Csqrt%7B%28x_1%20-%20x_2%29%5E2%20%2B%20%28y_1%20-%20y_2%29%5E2%7D%7D)
So, we have:
![\mathbf{EF = \sqrt{(-1 - 4)^2 + (-2 - -2)^2}}](https://tex.z-dn.net/?f=%5Cmathbf%7BEF%20%3D%20%5Csqrt%7B%28-1%20-%204%29%5E2%20%2B%20%28-2%20-%20-2%29%5E2%7D%7D)
![\mathbf{EF = \sqrt{25}}](https://tex.z-dn.net/?f=%5Cmathbf%7BEF%20%3D%20%5Csqrt%7B25%7D%7D)
![\mathbf{EF = 5}](https://tex.z-dn.net/?f=%5Cmathbf%7BEF%20%3D%205%7D)
Add 5 to the y-coordinates of E and F
![\mathbf{C = (-1,-2+5)}](https://tex.z-dn.net/?f=%5Cmathbf%7BC%20%3D%20%28-1%2C-2%2B5%29%7D)
![\mathbf{C = (-1,3)}](https://tex.z-dn.net/?f=%5Cmathbf%7BC%20%3D%20%28-1%2C3%29%7D)
![\mathbf{D = (4,-2+5)}](https://tex.z-dn.net/?f=%5Cmathbf%7BD%20%3D%20%284%2C-2%2B5%29%7D)
![\mathbf{D = (4,3)}](https://tex.z-dn.net/?f=%5Cmathbf%7BD%20%3D%20%284%2C3%29%7D)
Subtract 5 to the y-coordinates of E and F
![\mathbf{C = (-1,-2-5)}](https://tex.z-dn.net/?f=%5Cmathbf%7BC%20%3D%20%28-1%2C-2-5%29%7D)
![\mathbf{C = (-1,-7)}](https://tex.z-dn.net/?f=%5Cmathbf%7BC%20%3D%20%28-1%2C-7%29%7D)
![\mathbf{D = (4,-2-5)}](https://tex.z-dn.net/?f=%5Cmathbf%7BD%20%3D%20%284%2C-2-5%29%7D)
![\mathbf{D = (4,-7)}](https://tex.z-dn.net/?f=%5Cmathbf%7BD%20%3D%20%284%2C-7%29%7D)
Hence, the coordinates of the other pairs are: (-1, 3), (4, 3) and (-1, -7), (4, -7)
There is no third pair
Read more about vertices at:
brainly.com/question/2791243