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Lina20 [59]
3 years ago
13

Steps

Mathematics
1 answer:
slamgirl [31]3 years ago
5 0

Answer:

step 2

Step-by-step explanation:

Given

(2x - 3)(5x² - 2x + 7)

2x(5x² - 2x + 7) = 10x³ - 4x² + 14x ← step 1 is correct

- 3(5x² - 2x + 7) = - 15x² + 6x - 21 ← step 2 in her working is incorrect

Adding the results from step 1 and step 2

10x³ - 4x² + 14x - 15x² + 6x - 21 ← collect like terms

= 10x³ - 19x² + 20x - 21

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Rosa and her friends are eating out for dinner. the bill was $30.12. they want to leave a 19% tip.
FromTheMoon [43]

Answer:

35.84

Step-by-step explanation:

You would take 19% of 30.12$ by doing 30.12x0.19 to get 5.72.

you then add 5.72 to 30.12 to get your total of 35.84$

7 0
2 years ago
Which of the following expressions is equal to -3X2-27?
ale4655 [162]

Answer: B

Step-by-step explanation:

-3x^2-9xi+9ix-27

-3x^2-27

8 0
3 years ago
I don't know if this is right... please someone help mee
worty [1.4K]
For the first circle, let's use the pythagorean theorem

\bf \textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{8^2+15^2}\implies c=\sqrt{289}\implies c=17

now, it just so happen that the hypotenuse on that triangle, is actually 17, but we used the pythagorean theorem to find it, and the pythagorean theorem only works for right-triangles.

 so if the hypotenuse is actually 17, that means that triangle there is actually a right-triangle, meaning that the radius there, and the outside line there, are both meeting at a right-angle.

when an outside line touches the radius line, and they form a right-angle, the outside line is indeed a tangent line, since the point of tangency is always a right-angle with the radius.



now, let's check for second circle

\bf \textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{11^2+14^2}\implies c=\sqrt{317}\implies c\approx 17.8044938

well, low and behold, we didn't get our hypotenuse as 16 after all, meaning, that triangle is NOT a right-triangle, and that outside line is not touching the radius at a right-angle, therefore is NOT a tangent line.



let's check the third circle

\bf \textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{33^2+56^2}\implies c=\sqrt{4225}\implies c=\stackrel{33+32}{65}

this time, we did get our hypotenuse to 65, the triangle is a right-triangle, so the outside line is indeed a tangent line.
6 0
3 years ago
Which graph represents the function y = 3*+2?
puteri [66]

Answer:

We can graph y = 2x/3 - 2 to find the line.

We know one point, which is the y-intercept. The y-intercept is (0,-2) so that is our first point. Plot that point on the chart. Now to find another point, we can just insert a number for x and solve for y. I am going to use the number 3.

y = 2x/3 - 2

y = 2(3)/3 - 2

y = 6/3 - 2

y = 2 - 2

y = 0

So when x = 3 y = 0. We have another point,which is (3,0) Plot the points (0, -2) (3, 0) and draw a line between the points and that is your graph.

there ya go

5 0
3 years ago
H(x) = -x - 1, find h(-2)
eduard

Answer:

I think the answer is 1

Step-by-step explanation:

-(-2)-1

=1

6 0
3 years ago
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