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zvonat [6]
3 years ago
6

What is not true about the absolute value of -6

Mathematics
1 answer:
Sidana [21]3 years ago
3 0
Is there answer choices ?
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Identify the reflection of the figure with vertices E(8,4), F(-16,-8), and G(24,-16) across the y-axis.
Dafna1 [17]

Answer:

\boxed{\text{E$'$(-8, 4), F$'$(16,-8), G$'$(-24,-16)}}

Step-by-step explanation:

When you reflect a point (x, y) in the y-axis, the y-coordinate remains the same, but the x-coordinate gets the opposite sign. Thus,

E (8,4) ⟶ E' (-8,4)

F (-16,-8) ⟶ F' (16,-8)

G (24,-16) ⟶ G' (-24,-16)

\text{The reflected figure has coordinates } \boxed{\textbf{E$'$(-8, 4), F$'$(16,-8), G$'$(-24,-16)}}

The figure EFG and its reflection E'F'G' are shown in the diagram below.

6 0
3 years ago
What measure is represented by 17 feet in the figure below?
artcher [175]

Answer:

The diameter of the base.

Step-by-step explanation:

If the cylinder has a diameter of 17 feet, then the diameter of said cylinder's base will be 17 feet.

5 0
3 years ago
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The sum of two numbers is 25. One number
nevsk [136]

Answer:

the numbers are 9 and 16

hope it helps

8 0
3 years ago
1\2 ÷ 1\2 i dont know the please help
marysya [2.9K]

Answer:

I think 1/2 divided 1/2 is equal to 1

Step-by-step explanation:

I put in into the calculator and it said 1

7 0
3 years ago
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Show that the roots of the equations
harkovskaia [24]

Answer:

The roots are real and distinct.

Step-by-step explanation:

Given the following equation:

x^{2} + kx - k -2 =0

In this problem, a = 1, b = k and c = -k - 2

The discriminant is b² - 4ac, and for the roots to be real and distinct, it must be at least or greater than 0.

We get,

(k)²- 4(1)(-k - 2) = 1 - 4(-k - 2)

= k² + 4k + 8

Let's check:

At k = -2,

(-2)^{2} + 4(-2) + 8 = 4 - 8 + 8 = 4




At k = 0,

(0)^2 + 4(0) + 8 = 8

At k = -100,

(-100)^2 + 4(-100) + 8 = 10,000 - 400 + 8 = 9608

Therefore, we can conclude that for all values of k, the roots are real and distinct.

This has been a long way in answering this question, so it would be great if you could mark me as brainliest

3 0
3 years ago
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