1. Getting either all heads or all tails is a 1/1024 chance
2. Rolling a pair of dice and getting a sum of one has a chance of 0
3. Rolling a sum of 5 has a 2 in 21 chance
4. Rolling a sum of 12 has a 1 in 21 chance
A turning point occurs when the velocity is equal to zero, but the acceleration is not equal to zero.
t(x)=(x+5)^3+7
dt/dx=3(x+5)^2
d2t/dx2=6(x-5)
dt/dx=0 only when x=-5
However, since d2t/dx2(-5)=0, this point is an inflection point, not a turning point.
So there is no turning point for this function.
Now in this problem, it is even easier than the above to show that there is no turning point. A turning point by definition is when the derivative or velocity changes sign. Since in this case v=3(x+5)^2, for any value of x, v≥0, and thus never becomes negative, so it never changes from a positive to negative velocity because velocity in this instance is a squared function.
Answer:2.50cm
Step-by-step explanation:
The answer could be 45 but I'm not entirely sure
Answer:
x - 5y = 22
Step-by-step explanation:
Step 1: rewrite the equation of the given line in to slope-intercept form by solving for y
x = 5y - 9
-5y = -x - 9 (subtract 5y and x from both sides)
y = x/5 + 9/5 (divide both side by -5)
Step 2: Our line is parallel to this line, so it has the same slope, but a different y-intercept, so set up the equation...
y = x/5 + b
We are given a point (x, y) of (2, -4), so plug that in and solve for b.
-4 = 2/5 + b
-4 - 2/5 = b (subtract 2/5 from both sides to isolate b)
-20/5 - 2/5 = b
-22/5 = b (simplify)
So the equation of our line is y = x/5 - 22/5
Step 3: Standard form is ax + by = c, where a is a positive integer
subtract x/5 from both sides...
-x/5 + y = - 22/5
multiply by -5 so x becomes a positive integer
x - 5y = 22