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RSB [31]
2 years ago
10

Help if you can I really need to finish this

Mathematics
1 answer:
WINSTONCH [101]2 years ago
6 0
Number 4 is F
Number 5 is B
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F(x)=-3x-2 find f(3)
TiliK225 [7]

Answer:

f(3) = -11

Step-by-step explanation:

f(x) = -3x-2

let x=3 and replace it in the above equation

f(3) = -3(3) -2

f(3) = -9 -2

f(3) = -11


4 0
3 years ago
The temperature was -11. By noon, it increased by 12. What was the temperature at noon?
Leona [35]
The temperature was 1 because of you add them
-11+12=1
8 0
3 years ago
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What is -4/5x-2=18 what is x help quick
mart [117]

Answer:

If I'm right x= -25

Step-by-step explanation:

6 0
3 years ago
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There are 15 identical pens in your drawer, nine of which have never been used. On Monday, yourandomly choose 3 pens to take wit
DaniilM [7]

Answer: p = 0.9337

Step-by-step explanation: from the question, we have that

total number of pen (n)= 15

number of pen that has never been used=9

number of pen that has been used = 15 - 9 =6

number of pen choosing on monday = 3

total number of pen choosing on tuesday=3

note that the total number of pen is constant (15) since he returned the pen back .

probability of picking a pen that has never been used on tuesday = 9/15 = 3/5

probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5

probability of picking a pen that has been used on tuesday = 6/15 = 2/5

probability of not picking a pen that has not been used on tuesday= 1- 2/5= 3/5

on tuesday, 3 balls were chosen at random and we need to calculate the probability that none of them has never been used .

we know that

probability of ball that none of the 3 pen has never being used on tuesday = 1 - probability that 3 of the pens has been used on tuesday.

to calculate the probability that 3 of the pen has been used on tuesday, we use the binomial probability distribution

p(x=r) = nCr * p^{r} * q^{n-r}

n= total number of pens=15

r = number of pen chosen on tuesday = 3

p = probability of picking a pen that has never been used on tuesday = 9/15 = 3/5

q = probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5

by slotting in the parameters, we have that

p(x=3) = 15C3 * (\frac{2}{5})^{3} * (\frac{3}{5})^{12}

p(x=3) = 455 * 0.4^{3} * 0.6^{12}

p(x=3) = 455 * 0.064 * 0.002176

p(x=3) = 0.0633

thus probability that 3 of the pens has been used on tuesday. = 0.0633

probability of ball that none of the 3 pen has never being used on tuesday  = 1 - 0.0633 = 0.9337

3 0
3 years ago
Andy has two similar conical hats, Hat A and Hat B. The diameter of Hat A is 18 inches, and the diameter of Hat B is 9 inches. W
alex41 [277]
I think it 8:1 not for sure

8 0
3 years ago
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