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3 years ago

Which shape can also be all of the other shapes listed based on the definitions of each shape?

1 answer:

5 0

Answer: kite: rhombus, square:rectangle, isosceles trapezoid: trapezoid, parallelogram: square, parallelogram: rhombus, parallelogram: rectangle, parallelogram: square

Good luck!!!

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What are the coordinates of point S?

xxMikexx [17]

CC. 2 units in positive x and 3 units in positive z

8 0

3 years ago

Alright to the nearest 100th now

kirill [66]

Answer:

28.26

Step-by-step explanation:

For this, we can simply use the pi times r squared because we have the radius.

simplify pi to 3.14, so we can do 3.14 times 3 squared.

we get 9x 3.14, which is 28.26.

8 0

3 years ago

Lesson: 1.08Given this function: f(x) = 4 cos(TTX) + 1Find the following and be sure to show work for period, maximum, and minim

Ber [7]

The given function is

$f(x)=4\cos \text{(}\pi x)+1$

The general form of the cosine function is

$y=a\cos (bx+c)+d$

a is the amplitude

2pi/b is the period

c is the phase shift

d is the vertical shift

By comparing the two functions

a = 4

b = pi

c = 0

d = 1

Then its period is

$\begin{gathered} \text{Period}=\frac{2\pi}{\pi} \\ \text{Period}=2 \end{gathered}$

The equation of the midline is

$y_{ml}=\frac{y_{\max }+y_{\min }}{2}$

Since the maximum is at the greatest value of cos, which is 1, then

$\begin{gathered} y_{\max }=4(1)+1 \\ y_{\max }=5 \end{gathered}$

Since the minimum is at the smallest value of cos, which is -1, then

$\begin{gathered} y_{\min }=4(-1)+1 \\ y_{\min }=-4+1 \\ y_{\min }=-3 \end{gathered}$

Then substitute them in the equation of the midline

$\begin{gathered} y_{ml}=\frac{5+(-3)}{2} \\ y_{ml}=\frac{2}{2} \\ y_{ml}=1 \end{gathered}$

The answers are:

Period = 2

Equation of the midline is y = 1

Maximum = 5

Minimum = -3

3 0

1 year ago

How would you choose to reduce the system shown to a 2 × 2? Explain why you would choose this approach. –3x + y – 2z = 10 (1) 5x

gladu [14]

-3x + y - 2z = 10 |* -1
3x - y +2z = -10
5x -2y -2z = 12
--------------------------- I add these equations term by term
8x - 3y = 2

-3x + y - 2z =10 ⇒ -3x + y - 2z =10
x -y +z = 23 | *2 2x - 2y + 2z = 46
----------------------------- I add these eq.
-x -y = 56

8x - 3y = 2
-x -y = 56

this is the system after i reduce it ( it has only two variables x and y)

4 0

3 years ago

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Gas mileage is the number of miles you can drive on a gallon of gasoline. A test of a new car results in 490 Miles's on 10 gallo

GenaCL600 [577]

Since it could drive 49 miles on 1 gallon, and this is also it's gas mileage, (because 490/10=49) it could drive 45 times more on 45 gallons than on one. So, we multiply 45 by 49 to get 2209 gallons on 45 gallons of gas.

7 0

4 years ago

Read 2 more answers