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777dan777 [17]
3 years ago
8

Talia used 1/3 of a piece of wood for the base of her project 1/4 of the piece of wood for the vertical support and the rest for

horizontal supposed what fraction of the wood did Talia use as a horizontal support.
Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
3 0

Answer:

The fraction of wood used for horizontal support is \frac{5}{12}.

Step-by-step explanation:

Assume that the total piece of wood is of length 1.

It is provided that Talia used \frac{1}{3} of the piece of wood for the base of he project.

She use \frac{1}{4} of the piece of wood for the for the vertical support.

The remaining wood she used for horizontal support.

The amount of wood used for horizontal support can be computed by the subtracting the amount of wood used for base of the project and vertical support form 1.

Compute the amount of wood used for horizontal support as follows:

Horizontal\ support=1-Base\ of\ project-Vertical\ support\\= 1 - \frac{1}{3}-\frac{1}{4}\\  =\frac{12-4-3}{12} \\=\frac{5}{12}

Thus, the fraction of wood used for horizontal support is \frac{5}{12}.

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In the previous part, we obtained dy dx = 3t2 − 27 −2t . Next, find the points where the tangent to the curve is horizontal. (En
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Answer:

(27.55, 7.22), (-11.3, 3.21).

Step-by-step explanation:

When is the tangent to the curve horizontal?

The tangent curve is horizontal when the derivative is zero.

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\frac{dy}{dx} = 3t^{2} - 2t - 27

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

3t^{2} - 2t - 27 = 0

So

a = 3, b = -2, c = -27

Then

\bigtriangleup = b^{2} - 4ac = (-2)^{2} - 4*3*(-27) = 328

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t_{2} = \frac{-(-2) - \sqrt{328}}{2*3} = -2.685

Enter your answers as a comma-separated list of ordered pairs.

We found values of t, now we have to replace in the equations for x and y.

t = 3.35

x = t^{3} - 3t = (3.35)^{3} - 3*3.35 = 27.55

y = t^{2} - 4 = (3.35)^2 - 4 = 7.22

The first point is (27.55, 7.22)

t = -2.685

x = t^{3} - 3t = (-2.685)^3 - 3*(-2.685) = -11.3

y = t^{2} - 4 = (-2.685)^2 - 4 = 3.21

The second point is (-11.3, 3.21).

8 0
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Uh help me please lol​
wel

Answer:

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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