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ki77a [65]
3 years ago
8

Can SOMEONE PLEASE HELP ME I NEED HELP!!!! :( PLEASEE

Mathematics
2 answers:
katovenus [111]3 years ago
7 0

Step-by-step explanation:

DE = 13

2 + 2x - 3 = 13

2x - 1 = 13

2x = 12

x = 12/2

x = 6

joja [24]3 years ago
4 0

Answer:

5).

According to the question,

CD+DE=CE

2+13=2x-3

15=2x-3

15+3=2x

18=2x

18/2=x

8=x

6).

According to the question,

AB+BC=AC

5x-16+3x-6=2x+20

8x-22=2x+20

8x-2x=20+22

6x=44

x=44/6

x=7.33

Step-by-step explanation:

......

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Find the length of PR¯¯¯¯¯¯¯
Ne4ueva [31]

Answer:

8x+4

Step-by-step explanation:

3x-2+5x+6

3x+5x-2+6

8x+4

4 0
4 years ago
Read 2 more answers
Pls help me this is a late paper and I am so confused!<br> x =7y -10<br> 3x-2y=8
AveGali [126]

Answer:

Yeah I would be too

Step-by-step explanation:

5 0
3 years ago
A. Solve the differential equation <img src="https://tex.z-dn.net/?f=y%27%3D2x%20%5Csqrt%7B1-y%5E2%7D%20" id="TexFormula1" title
kirill [66]
y' = \frac{dy}{dx}

seperable differential equations will have the form
\frac{dy}{dx} = F(x) G(y)

what you do from here is isolate all the y terms on one side and all the X terms on the other
\frac{dy}{G(y)} = F(x) dx
just divided G(y) to both sides and multiply dx to both sides

then integrate both sides
\int \frac{1}{G(y)} dy = \int F(x) dx&#10;&#10;

once you integrate, you will have a constant. use the initial value condition to solve for the constant, then try to isolate x or y if the question asks for it


In your problem,
G(y) = \sqrt{1-y^2}&#10;&#10;F(x) = 2x

so all you need to integrate is
\int \frac{1}{\sqrt{1-y^2}} dy = \int 2x dx
5 0
4 years ago
A train leaves the station and has to travel 486km. The train maintains a speed of 120km. After travelling for 3 hours and 15 mi
Anuta_ua [19.1K]

Answer:

I think its 2 hours 30 minutes

Step-by-step explanation:

7 0
3 years ago
Help with question 5a
Llana [10]
This is a refreshing question!

We are given that
f(r)=ar+b, and
Sum f(r) =125 for r=1 to 5
Sum f(r) = 475 for r=1 to 10.

and we know, using Gauss's method, that
G(n)=sum (1,2,3.....n) = n(n+1)/2 or
G(n)=n(n+1)/2

Sum f(r) =125 for r=1 to 5
=>
sum=a(sum of 1 to 5) + 5b => G(5)a+5b=125   [G(5)=15]
15a+5b=125 ...................................................(1)

Similarly, Sum f(r) =  475 for r=1 to 10 => G(10)a+5b=475  [G(10)=55]
=>
55a+10b=475.................................................(2)

Solve system of equations (1) and (2)
(2)-2(1)
55-2(15)a=475-2(125) => 25a=225 =>
a=9

Substitute a=9 in 1 => 15(9)+5b=125 => 5b=-10
b=-2

Substitute a and b into f(r), 
f(r)=9r-2
check: sum f(r), r=1,5 = (9-2)+(18-2)+(27-2)+(36-2)+(45-2)=135-10=125 [good]

We define the sum of f(r) for r=1 to n as
S(n)=sum f(r) for r=1 to n = 9(sum 1,2,3....n)-2n = 9n(n+1)/2-2n = 9G(n)-2n
S(n)=9n(n+1)/2-2n
checks:
S(5)=9(15)-2(5)=135-10=125  [good]
S(10)=9(55)-2(10)=495-20=475 [good]

Hence 
(a)
S(n)=sum f(r) for r=1,n
= 9(sum i=1,n)+n(-2)
= 9(n(n+1)/2 -2n
=(9(n^2+n)/2) -2n

(b) sum f(r) for i=8,18
=sum f(r) for i=1,18  -  sum f(r) for i=1,7
=S(18)-S(7)
=(9(18^2-18)/2-2(18))-(9(7^2-7)/2-2(7))
=1503-238
=1265
5 0
3 years ago
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