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ki77a [65]
3 years ago
8

Can SOMEONE PLEASE HELP ME I NEED HELP!!!! :( PLEASEE

Mathematics
2 answers:
katovenus [111]3 years ago
7 0

Step-by-step explanation:

DE = 13

2 + 2x - 3 = 13

2x - 1 = 13

2x = 12

x = 12/2

x = 6

joja [24]3 years ago
4 0

Answer:

5).

According to the question,

CD+DE=CE

2+13=2x-3

15=2x-3

15+3=2x

18=2x

18/2=x

8=x

6).

According to the question,

AB+BC=AC

5x-16+3x-6=2x+20

8x-22=2x+20

8x-2x=20+22

6x=44

x=44/6

x=7.33

Step-by-step explanation:

......

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Lunna [17]

Answer:

I believe C is the correct answer because the graph starts above 40 on y axis and D is incorrect because of the y + not y=

7 0
3 years ago
What is 481 divided by 8?Is it 60 with a remainder of 1 ?
Marizza181 [45]
Yes. 60 remain 1 or 60.125 . 
5 0
4 years ago
Which point is located at (–1, 3)? On a coordinate plane, point A is 1 unit to the right and 3 units down. Point B is 3 units to
Marizza181 [45]

Answer:

Point C.

Step-by-step explanation:

When the x-value is negative, the point is moving left. In this case, the point is moving left 1.

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4 0
3 years ago
HELPPPPPPP ASAPPPPPPPP PLSSSS
Novay_Z [31]

Answer:

the first one is. hope helps

5 0
3 years ago
PLEASE HELP I DO NOT UNDERSTAND AT ALL ITS PRECALC PLEASE SERIOUS ANSWERS
Elina [12.6K]

You want to end up with A\sin(\omega t+\phi). Expand this using the angle sum identity for sine:

A\sin(\omega t+\phi)=A\sin(\omega t)\cos\phi+A\cos(\omega t)\sin\phi

We want this to line up with 2\sin(4\pi t)+5\cos(4\pi t). Right away, we know \omega=4\pi.

We also need to have

\begin{cases}A\cos\phi=2\\A\sin\phi=5\end{cases}

Recall that \sin^2x+\cos^2x=1 for all x; this means

(A\cos\phi)^2+(A\sin\phi)^2=2^2+5^2\implies A^2=29\implies A=\sqrt{29}

Then

\begin{cases}\cos\phi=\frac2{\sqrt{29}}\\\sin\phi=\frac5{\sqrt{29}}\end{cases}\implies\tan\phi=\dfrac{\sin\phi}{\cos\phi}=\dfrac52\implies\phi=\tan^{-1}\left(\dfrac52\right)

So we end up with

2\sin(4\pi t)+5\cos(4\pi t)=\sqrt{29}\sin\left(4\pi t+\tan^{-1}\left(\dfrac52\right)\right)

8 0
3 years ago
Read 2 more answers
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