Question

A park designer wanted to place a fountain so that it was close to both the slide and the swings. Refer to the coordinate grid shown. Each unit on the grid represents 100 ft.
(A) find the distance from the slide to the foundation show your work.

(B) if each jump = 100ft, how far is it from the slide to the fountain?


Please show your work :)

Answer 1

Answer:

200 ft.

2 jumps

Step-by-step explanation:

The slide is placed at coordinates (-2,0) and the fountain is placed at coordinates (-2,-2).

(A) Therefore, using the distance between two known points formula, the distance from the slide to the fountain is given by  

$\sqrt{(-2 - ( -2))^{2} + (-2 - 0)^{2}} = \sqrt{(0 + 4)} = 2$ units.

Now, given that each unit on the grid represents 100 ft.

So, the distance from slide to the fountain is (100 × 2) = 200 ft. (Answer)

(B) Now, if each jump = 100 ft, then the slide is 2 jumps apart from the fountain. (Answer)

We know the distance between two known points on the coordinate plane ($x_{1},y_{1}$) and ($x_{2},y_{2}$) is given by the following formula

Distance = $\sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2} )^{2}}$