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3 years ago

What is (9/8)^3x+12=1

Mathematics

1 answer:

Ludmilka [50]3 years ago

6 0

Answer:

x = -88/27 = -3.259

Step-by-step explanation:

It was really hard to figure out but this should be it

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Translate the verbal statements into a system of linear equations: Fatima invested a total of $1000 in two simple-interest bank

mixas84 [53]

Answer:

Step-by-step explanation:

Translate the verbal statements into a system of linear equations: Fatima invested a total of $1000 in two simple-interest bank accounts. One account paid 5% annual interest; the other paid 6% annual interest. The total amount of interest she earned after 1 year was $56

Simple interest formula =

I = PRT

We are to find the Amount = Principal invested

For Account 1

I1 = P × 5% × 1

= 0.05P

Account 2

I2 = P × 6% × 1

= 0.06P

Therefore:

0.05P + 0.06P = $56

6 0

2 years ago

Without doing the math, determine which is greater, 40 . 1/4 or 40/14. explain your reasoning

BARSIC [14]

40 is greater because we can easily see that 1/4 is not a whole number that is less than 40 and the 40/14 will be changed into a lesser mixed number which again, is less than 40.

8 0

3 years ago

Solve the initial value problems:<br> 1/θ(dy/dθ) = ysinθ/(y^2 + 1); subject to y(pi) = 1

ladessa [460]

Answer:

$-\theta cos\thsta+sin\theta = \frac{y^{2} }{2} + ln y + \pi - \frac{1}{2}$

Step-by-step explanation:

Given the initial value problem $\frac{1}{\theta}(\frac{dy}{d\theta} ) =\frac{ ysin\theta}{y^{2}+1 } \\$ subject to y(π) = 1. To solve this we will use the variable separable method.

Step 1: Separate the variables;

$\frac{1}{\theta}(\frac{dy}{d\theta} ) =\frac{ ysin\theta}{y^{2}+1 } \\\frac{1}{\theta}(\frac{dy}{sin\theta d\theta} ) =\frac{ y}{y^{2}+1 } \\\frac{1}{\theta}(\frac{1}{sin\theta d\theta} ) = \frac{ y}{dy(y^{2}+1 )} \\\\\theta sin\theta d\theta = \frac{ (y^{2}+1)dy}{y} \\integrating\ both \ sides\\\int\limits \theta sin\theta d\theta =\int\limits \frac{ (y^{2}+1)dy}{y} \\-\theta cos\theta - \int\limits (-cos\theta)d\theta = \int\limits ydy + \int\limits \frac{dy}{y}$

$-\theta cos\thsta+sin\theta = \frac{y^{2} }{2} + ln y +C\\Given \ the\ condition\ y(\pi ) = 1\\-\pi cos\pi +sin\pi = \frac{1^{2} }{2} + ln 1 +C\\\\\pi + 0 = \frac{1}{2}+ C \\C = \pi - \frac{1}{2}$

The solution to the initial value problem will be;

$-\theta cos\thsta+sin\theta = \frac{y^{2} }{2} + ln y + \pi - \frac{1}{2}$

5 0

2 years ago

Solve for X<br> 9x + 2 = 3<br> Give your answer as a fraction in its simplest form.

kati45 [8]

Answer:x=1/9

Step-by-step explanation:

1. subtract 2 from both sides

9x+2-2=3-2

2.simplify

9x=1

3.Divide both sides by 9

9x/9=1/9

4.simplify

x=1/9

4 0

2 years ago

Read 2 more answers

If c = 13 and A = 73º, find a. Round to the nearest tenth.

marysya [2.9K]

Answer: 34

Step-by-step explanation:

5 0

2 years ago