Question

PLz help

Answer 1

Answer:

So you will want to graph the following 3 points:

(0,2)

(3,3)

(-3,1)

Then connect the points.

Step-by-step explanation:

So we have the equation x-3y=-6.

I'm going to solve for y once so I don't have to do it 3 times when choosing a value for x.

x-3y=-6

Subtract x on both sides:

 -3y=-x-6

Divide both sides by -3:

   $y=\frac{-x}{-3}+\frac{-6}{-3}$

Simplify where you can:

  $y=\frac{1}{3}x+2$

So since this in the slope-intercept form, y=mx+b where slope is m and b is y-intercept we have that (0,2) is on our line.  If you plug in 0, you will get 2 like this y=1/3 (0)+2=0+2=2.  

Now I'm going to choose easy values to plug in, ones that are divisible by 3 since x is being multiplied by 1/3.

So if x=3, then $y=\frac{1}{3}(3)+2=1+2=3$, so (3,3) is on the line.

So if x=-3, then $y=\frac{1}{3}(-3)+2=-1+2=1$. so (-3,1) is on the line.

So you will want to graph the following 3 points:

(0,2)

(3,3)

(-3,1)