Ask question

Ask question

All categories

2 years ago

14

Find the lateral area of a cylinder with the given measurements. Use 3.14 for π and round your answer to the nearest tenth. Heig

ht: 15 centimeters Radius: 9 centimeters

2 answers:

Zolol [24]2 years ago

6 0

Answer:Lateral surface area is 847.8 centimeters^2

Step-by-step explanation:

The formula for determining the lateral surface area of a cylinder is expressed as

Lateral surface area = 2πrh

Where

r = radius of the cylinder

h = the height of the cylinder

From the information given,

r = 9 centimeters

h = 15 centimeters

π = 3.14

Lateral surface area = 2 × 3.14 × 9 × 15 = 847.8 centimeters^2

Yuliya22 [10]2 years ago

5 0

Answer:

Lateral surface area is 847.8 centimeters^2 is the correct answer.

Step-by-step explanation:

You might be interested in

In a video store, a DVD that sells for $15 is marked "10% off." What is the discount? What is the sale price of the DVD?

Margarita [4]

Answer:

it will be 1.50$ off as the discount so sold for 13.50 is the sale price

8 0

2 years ago

Read 2 more answers

2-13^3-10(23+21) = X

Tanya [424]

Answer:

x= -2635

Step-by-step explanation:

2 - 2197 - 10 x 44 = x

2- 2197 - 440 = x

-2635 = x

8 0

2 years ago

Read 2 more answers

The Department of Agriculture is monitoring the spread of mice by placing 100 mice at the start of the project. The population,

uranmaximum [27]

Answer:

Step-by-step explanation:

Assuming that the differential equation is

$\frac{dP}{dt} = 0.04P\left(1-\frac{P}{500}\right)$ .

We need to solve it and obtain an expression for $P(t)$ in order to complete the exercise.

First of all, this is an example of the logistic equation, which has the general form

$\frac{dP}{dt} = kP\left(1-\frac{P}{K}\right)$ .

In order to make the calculation easier we are going to solve the general equation, and later substitute the values of the constants, notice that $k=0.04$ and $K=500$ and the initial condition $P(0)=100$ .

Notice that this equation is separable, then

$\frac{dP}{P(1-P/K)} = kdt$ .

Now, intagrating in both sides of the equation

$\int\frac{dP}{P(1-P/K)} = \int kdt = kt +C$ .

In order to calculate the integral in the left hand side we make a partial fraction decomposition:

$\frac{1}{P(1-P/K)} = \frac{1}{P} - \frac{1}{K-P}$ .

So,

$\int\frac{dP}{P(1-P/K)} = \ln|P| - \ln|K-P| = \ln\left| \frac{P}{K-P} \right| = -\ln\left| \frac{K-P}{P} \right|$ .

We have obtained that:

$-\ln\left| \frac{K-P}{P}\right| = kt +C$

which is equivalent to

$\ln\left| \frac{K-P}{P}\right|= -kt -C$

Taking exponentials in both hands:

$\left| \frac{K-P}{P}\right| = e^{-kt -C}$

Hence,

$\frac{K-P(t)}{P(t)} = Ae^{-kt}$ .

The next step is to substitute the given values in the statement of the problem:

$\frac{500-P(t)}{P(t)} = Ae^{-0.04t}$ .

We calculate the value of $A$ using the initial condition $P(0)=100$ , substituting $t=0$ :

$\frac{500-100}{100} = A}$ and $A=4$ .

So,

$\frac{500-P(t)}{P(t)} = 4e^{-0.04t}$ .

Finally, as we want the value of $t$ such that $P(t)=200$ , we substitute this last value into the above equation. Thus,

$\frac{500-200}{200} = 4e^{-0.04t}$ .

This is equivalent to $\frac{3}{8} = e^{-0.04t}$ . Taking logarithms we get $\ln\frac{3}{8} = -0.04t$ . Then,

$t = \frac{\ln\frac{3}{8}}{-0.04} \approx 24.520731325$ .

So, the population of rats will be 200 after 25 months.

6 0

2 years ago

Use the graph of the function f to find f(-1)

Vikki [24]

We need the graph!!!!!!!

7 0

2 years ago

Read 2 more answers

Which of the following describes the image of a triangle after a dilation that has a scale factor of 5/6

Sergeeva-Olga [200]

Answer:

See example below.

Step-by-step explanation:

The image of a triangle will be 5/6 the size. It will be slightly smaller than the original. For example, if the side measurement of the triangle on one side is 12 then the image of the triangle after a dilation will be 12*5/6 = 60/6 = 10.

The new side length is 10 slightly smaller than 12.

6 0

2 years ago