The 5 rotational levels would there be between the ground vibrational state and the first excited vibrational state.
What is rotational levels?
The three major moments of inertia IA, IB, and IC determine the rotational energy levels for a nonlinear molecule. They revolve around three axes that are mutually orthogonal to one another and have their origin (or intersection) at the molecule's Centre of mass.
What is vibrational state?
The rotation of the molecule brought on by various vibrations in perpendicular planes is described by (123) or (12l23), where 0 l2 2 is an angular momentum quantum number.
Therefore , 5 rotational levels would there be between the ground vibrational state and the first excited vibrational state.
Learn more about rotational levels from the given link.
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The gas molecules bump into each other more frequently. The gas could turn into a liquid if it is also combined with a lowered temperature.<span />
Answer:
pH = 2.059
Explanation:
At the Cathode:
The reduction reaction is:
At the anode:
At oxidation reaction is:
The overall equation for the reaction is:
The overall cell potential is:
Using the formula for the Nernst equation:
where;
E = 0.66
(Zn^2+)=0.22 M
Then
![0.66 =0.76- ( \dfrac{0.0591}{2})log \bigg ( \dfrac{[Zn^{2+} ] PH_2}{[H^+]^2} \bigg )](https://tex.z-dn.net/?f=0.66%20%3D0.76-%20%28%20%5Cdfrac%7B0.0591%7D%7B2%7D%29log%20%5Cbigg%20%28%20%5Cdfrac%7B%5BZn%5E%7B2%2B%7D%20%5D%20PH_2%7D%7B%5BH%5E%2B%5D%5E2%7D%20%5Cbigg%20%29)
![0.66 =0.76- 0.02955 * log \bigg ( \dfrac{0.22*0.87}{[H^+]^2} \bigg )](https://tex.z-dn.net/?f=0.66%20%3D0.76-%200.02955%20%2A%20log%20%5Cbigg%20%28%20%5Cdfrac%7B0.22%2A0.87%7D%7B%5BH%5E%2B%5D%5E2%7D%20%5Cbigg%20%29)
3.4 = log ( 0.1914) - 2 log [H⁺]
3.4 = -0.7180 - 2 log [H⁺]
3.4 + 0.7180 = - 2 log [H⁺]
4.118 = - 2 log [H⁺]
pH = log [H⁺] = 4.118/2
pH = 2.059
I feel like it's the all the above but if it had to be one choice then I think it's the type of climate from which it came.
The added KI does not have any impact
The reaction invovles Titration of vitaminc ( Ascorbic acid)
ascorbic acid + I₂ → 2 I⁻ + dehydroascorbic acid
the excess iodine is free reacts with the starch indicator, forming the blue-black starch-iodine complex.
This is the endpoint of the titration. since alreay excess KI is added ( the source of Iodine), it does not have an influence.
Answer B
Hope this helps!
