C: Lithium. Before it was 4Li and after the oxidation it turned out to 2Li
Water containing carbonic acid and calcium
The volume occupied by 0.102 mole of the helium gas is 2.69 L
<h3>Data obtained from the question</h3>
The following data were obtained from the question:
- Number of mole (n) = 0.102 moles
- Pressure (P) = 0.95 atm
- Temperature (T) = 305 K
- Gas constant (R) = 0.0821 atm.L/Kmol
- Volume (V) =?
<h3>How to determine the volume </h3>
The volume of the gas can be obtained by using the ideal gas equation as illustrated below:
PV = nRT
Divide both sides by P
V = nRT / P
V = (0.102 × 0.0821 × 305) / 0.95
V = 2.69 L
Thus, the volume of the gas is 2.69 L
Learn more about ideal gas equation:
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My thought would be B) gases.
I could be wrong but that's what i'd say
Answer:
V=25.133 cm^3
(Is 4 the diameter you were given? To get one of those answers, I think you May have put the wrong diameter)
Explanation:
Radius is diameter/2
R=4/2
R=2
Volume of a sphere=4/3πr3
V=4/3π(2)3
V=25.133 cm^3
