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olganol [36]
3 years ago
9

I am having trouble predicting this equation. "Coke will reduce hot arsenious oxide to pure arsenic (As4). With the 4 as the sub

script.
Chemistry
1 answer:
Rudik [331]3 years ago
7 0
Well, Coke is just carbon in chemical reaction, so I think you get: 3 C + 2 As2O3--> 4 As + 3 CO2. Hope this helps! :)
You might be interested in
Nicotine, a component of tobacco, is composed of c, h, and n. a 4.200-mg sample of nicotine was combusted, producing 11.394 mg o
Rudiy27

Answer:

            Empirical Formula  =  C₅H₇N₁

Solution:

Data Given:

                      Mass of Nicotine  =  4.20 mg  =  0.0042 g

                      Mass of CO₂  =  11.394 mg  =  0.011394 g

                      Mass of H₂O  =  3.266 mg  =  0.003266 g

Step 1: Calculate %age of Elements as;

                      %C  =  (mass of CO₂ ÷ Mass of sample) × (12 ÷ 44) × 100

                      %C  =  (0.011394 ÷ 0.0042) × (12 ÷ 44) × 100

                      %C  =  (2.7128) × (12 ÷ 44) × 100

                      %C  =  2.7128 × 0.2727 × 100

                      %C  =  73.979 %


                      %H  =  (mass of H₂O ÷ Mass of sample) × (2.02 ÷ 18.02) × 100

                      %H  =  (0.003266 ÷ 0.0042) × (2.02 ÷ 18.02) × 100

                      %H  =  (0.7776) × (2.02 ÷ 18.02) × 100

                      %H  =  0.7776 × 0.1120 × 100

                      %H  =  8.709 %


                      %N  =  100% - (%C + %H)

                      %N  =  100% - (73.979 % + 8.709%)

                      %N  =  100% - 82.688%

                      %N  =  17.312 %

Step 2: Calculate Moles of each Element;

                      Moles of C  =  %C ÷ At.Mass of C

                      Moles of C  = 73.979 ÷ 12.01

                     Moles of C  =  6.1597 mol


                      Moles of H  =  %H ÷ At.Mass of H

                      Moles of H  = 8.709 ÷ 1.01

                      Moles of H  =  8.6227 mol


                      Moles of N  =  %N ÷ At.Mass of O

                      Moles of N  = 17.312 ÷ 14.01

                      Moles of N  =  1.2356 mol

Step 3: Find out mole ratio and simplify it;

                C                                        H                                     N

            6.1597                               8.6227                             1.2356

     6.1597/1.2356                  8.6227/1.2356                 1.2356/1.2356

               4.985                             6.978                                   1

             ≈ 5                                      ≈ 7                                     1

Result:

        Empirical Formula  =  C₅H₇N₁

6 0
3 years ago
In a synthesis reaction you start with 1.7L of Hydrogen how many liters of water will be produced?
Masteriza [31]

1.7 liters of water will be produced.

Explanation:

The balanced chemical reaction is:

2H2+ 02⇒ 2H20

Considering the reaction to be at STP (P = 1atm, V= 22.4 L, T = 273.15 K)

the formula used is:

PV = nRT

Where P, R and T remains same only volume and number of moles are different so,

\frac{Vhydrogen}{V water} = \frac{nhydrogen}{nwater}

observing the balanced reaction:

mole ratio is 2:2 i.e 1:1

so volume ratio will also be same

so 1.7 litres of water will be produced.

From the reaction it is seen that

1 mole hydrogen react with oxygen to give 1 mole of water at STP.

so, it is found that 1.7 liters of hydrogen gives 1.7 liters of water

3 0
3 years ago
Which statement about crystal lattice energy is best supported by the information in the table
Nat2105 [25]

The lattice energy increases as cations get smaller, as shown by LiF and KF.


OR


The lattice energy increases as the charge of anions increases, as shown by LiF and LiCl. The answer is B.

7 0
3 years ago
Select all that apply. which of the following are density labels? kg/l g/m g/ml cm^3/g
Strike441 [17]
I would say that only the only density label is cm^3/g
4 0
3 years ago
Read 2 more answers
5) Usted empuja muy fuerte un escritorio pesado e intenta moverlo. Usted efectúa trabajo sobre el escritorio: a.- Ya sea que lo
saul85 [17]

Answer:

5) You push hard on a heavy desk and try to move it. You do work on the desk: A.- Whether you move it or not, as long as you exert a force. B.- Only if the desktop moves. C.- Only if the desktop does not move. D.- Never; the desk does work on you. E.- None of the above. CAN YOU HELP ME?

B.- Only if the desktop moves.

Explanation:

No work is done if a force is exerted but no displacement occurs. A force perpendicular to the displacement does no generate work.

5 0
3 years ago
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