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faltersainse [42]
3 years ago
13

When a field is declared static, there will be:

Chemistry
1 answer:
Arturiano [62]3 years ago
5 0

Answer:

B. only one copy of the field in memory

Explanation:

A static method is sort of a description of a class but is not part of the objects that it generates. Crucial: A program may perform a static method without constructing an object first! All other functions (those not static) only occur when they're member of an object. Thus it is necessary to build an object before they could be executed.

Therefore, when an static field is declared static, there will be:

B. only one copy of the field in memory

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$1246.90

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Since the bike lost 20%% of it's value and it now currently at $$1039, we have to do 20% * $1039 to find the amount of money lost. 20%*1039=207.8. We have to add it up to find the original value so 1039+207.8=$1246.8

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Calculate ΔHrxn for the following reaction: 5C(s) 6H2(g)→C5H12(l) Use the following reactions and given ΔH values: C5H12(l) 8O2(
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Answer: its 4xb236.52

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What does an arrow in a chemical equation show?
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How many grams of chlorine gas are present in a 150. liter cylinder of chlorine held at a pressure of 1.00 atm and 0. °C? Group
OlgaM077 [116]

Answer:

474 grams of chlorine gas are present in a 150 liter cylinder of chlorine held at a pressure of 1.00 atm and 0 °C

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

In this case:

  • P= 1.00 atm
  • V= 150 L
  • n= ?
  • R= 0.082 \frac{atm*L}{mol*K}
  • T= 0 C= 273 K

Replacing:

1.00 atm* 150 L= n*0.08206 \frac{atm*L}{mol*K} *273 K

Solving:

n=\frac{1.00 atm* 150 L}{0.08206 \frac{atm*L}{mol*K}*273 K}

n= 6.69 moles

Being Cl= 35.45 g/mole, the molar mass of chlorine gas is:

Cl₂=2*35.45 g/mole= 70.9 g/mole

So if 1 mole has 70.9 grams, 6.69 moles of the gas, how much mass does it have?

mass=\frac{6.69 moles*70.9 grams}{1 mole}

mass= 474.321 grams ≅ 474 grams

<u><em>474 grams of chlorine gas are present in a 150 liter cylinder of chlorine held at a pressure of 1.00 atm and 0 °C</em></u>

4 0
3 years ago
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