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galben [10]
2 years ago
12

The line of a best fit is called​

Chemistry
1 answer:
Bad White [126]2 years ago
3 0
The line of best fit (or trendline) is an educated guess about where a linear equation might fall in a set of data plotted on a scatter plot
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bearhunter [10]

Answer:

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Explanation:

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6 0
3 years ago
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A system fitted with a piston expands when it absorbs 53.1 ) of heat from the surroundings. The piston is working against a pres
Hoochie [10]

Answer:

d. 60.8 L

Explanation:

Step 1: Given data

  • Heat absorbed (Q): 53.1 J
  • External pressure (P): 0.677 atm
  • Final volume (V2): 63.2 L
  • Change in the internal energy (ΔU): -108.3 J

Step 2: Calculate the work (W) done by the system

We will use the following expression.

ΔU = Q + W

W = ΔU - Q

W = -108.3 J - 53.1 J = -161.4 J

Step 3: Convert W to atm.L

We will use the conversion factor 1 atm.L = 101.325 J.

-161.4 J ×  1 atm.L/101.325 J = -1.593 atm.L

Step 4: Calculate the initial volume

First, we will use the following expression.

W = - P × ΔV

ΔV = - W / P

ΔV = - 1.593 atm.L / 0.677 atm = 2.35 L

The initial volume is:

V2 = V1 + ΔV

V1 = V2 - ΔV

V1 = 63.2 L - 2.35 L = 60.8 L

7 0
3 years ago
You place a balloon in a closed chamber at STP. When the balloon doubles in size, what happens to the chamber pressure? A.) The
larisa86 [58]
If you increase the volume the pressure will decrease.  so the best answer is C
4 0
3 years ago
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3. A 31.2-g piece of silver (s = 0.237 J/(g · °C)), initially at 277.2°C, is added to 185.8 g of a liquid, initially at 24.4°C,
VARVARA [1.3K]

Answer:

Cp_{liquid}=2.54\frac{J}{g\°C}

Explanation:

Hello,

In this case, since silver is initially hot as it cools down, the heat it loses is gained by the liquid, which can be thermodynamically represented by:

Q_{Ag}=-Q_{liquid}

That in terms of the heat capacities, masses and temperature changes turns out:

m_{Ag}Cp_{Ag}(T_2-T_{Ag})=-m_{liquid}Cp_{liquid}(T_2-T_{liquid})

Since no phase change is happening. Thus, solving for the heat capacity of the liquid we obtain:

Cp_{liquid}=\frac{m_{Ag}Cp_{Ag}(T_2-T_{Ag})}{-m_{liquid}(T_2-T_{liquid})} \\\\Cp_{liquid}=\frac{31.2g*0.237\frac{J}{g\°C}*(28.3-227.2)\°C}{185.8g*(28.3-24.4)\°C}\\ \\Cp_{liquid}=2.54\frac{J}{g\°C}

Best regards.

6 0
3 years ago
PLS HELP-CHEMISTRY: What is the molar concentration of an ammonia solution in which there are 0.1557 grams
harina [27]

Answer: M = 0.036 M

Explanation: Solution attached:

First convert mass of NH3 to moles

Next convert volume in mL to L

Use the formula for Molarity

M = n / L

4 0
3 years ago
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