Answer:
The element with electron configuration 1s² 2s² 2p⁶ will most likely not........
Explanation:
Aromatic side chain exhibits an electronic excited state that is closer in energy to the ground state.
- In order to respond to this query, we must decide whether a peptide bond or an aromatic side chain is demonstrating an electronic exited state that is more closely related to the ground state in terms of energy.
- When our energy is as low as possible, we are in the ground state.
- What I want to point out is that if we can choose between the two options—peptide bond or aromatic side chain—without knowing the specific reasons, we can immediately rule out two potential answers.
- Consider what we already know about energy, we have:
E = h x c/λ
- That indicates that when we have more energy, a wavelength decreases. Lower energy corresponds to higher wavelength.
- Aromatic side chains absorb between 250 and 290 nm, while peptide bonds do so between 190 and 250 nm.
- According to our breakdown, we have an electron excited state that is more closely related to the ground state in terms of energy as wavelength increases.
Thus, Aromatic side chain exhibits an electronic excited state that is closer in energy to the ground state.
To view similar questions about energy, refer to:
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Answer:
Wavelenght is 7,79x10⁻⁵ m
Explanation:
The equation that connects wavelentgh (λ) and frequency (ν) is:
λ=c/ν
Where c is speed of light (3x10⁸ m/sec) and λ is expressed in lenght´s units and ν is expressed in "time⁻¹ " units (for example, sec⁻¹)
According to the details, if we just replace the given value of frequency, we just obtaing wavelenght data:
λ= (3x10⁸ m/sec)/(3,85x10¹² sec⁻¹) = 7,79x10⁻⁵ m
Answer:
Option b.
The triple point of a substance is the temperature and pressure conditions at which states of a substance coexist at equilibrium
