Answer:
11860.22 rev/hour
Step-by-step explanation:
The diameter if a cylinder, d = 21.02 inches
Radius, r = 10.51 inches
or
r = 0.875 feet
The linear speed of a point on the cylinder's surface is 18.12 ft/sec.
We need to find the angular speed of the cylinder.
The relation between the linear speed and the angular speed is given by :

Where
is angular speed

or

So, the required angular speed of the cylinder is 11860.22 rev/hour.
Answer:A. h(t) = -16(t - 403)^2 + 3
B. h(t) = -16(t - 5)^2 + 3
C. h(t) = -16(t - 3)^2 + 403
D. h(t) = -16(t - 5)^2 + 403
Step-by-step explanation:
The answer is 10. 2 and 5 are not divisible by the same number except one, so you multiply it by each other to get 10.
Answer:
20kg
Step-by-step explanation:
There are 2.2 pounds in a kg, so we will divide 44 by 2.2 to see how many kg are in 44 pounds