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Amiraneli [1.4K]
2 years ago
8

The coordinates of the vertices of quadrilateral DEFG are D(−3, −1) , E(−6, 3) , F(3, 12) , and G(7, 9) .

Mathematics
2 answers:
nexus9112 [7]2 years ago
7 0
Your answer is D.
Because there are no negative reciprocals, therefore there are no right angles.
dolphi86 [110]2 years ago
5 0

Answer:

Quadrilateral DEFG is not a rectangle because it has no right angles.

Step-by-step explanation:

Plotting the coordinate points, we have a quadrilateral but not a rectangle. Looking at the points and the angles formed, we see that there do not have any right angle. In addition to this, whenever we have a rectangle we have common coordinates, like the second picture.

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Given: m∠1 = 140°, find m∠6.
zavuch27 [327]
<h2><em><u>Ans</u></em><em><u>wer</u></em><em><u>:</u></em></h2>

Let m<6 be X

140° + X = 180°

X = 180° - 140°

X =40°

5 0
3 years ago
Would love some help
natali 33 [55]
<h3>Answer: 90 cubic meters</h3>

Each triangle has a base of 10 and height of 3.6

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multiply this with the height of the prism (5 meters) to get 18*5 = 90 cubic meters. I'm using the idea that,

volume of prism = (area of base face)*(height of prism)

The notation "m^3" is shorthand for "cubic meters"

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7 0
3 years ago
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lesya692 [45]

Answer:

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Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
A chemical factory has 2 cylindrical chemical tanks, one containing Chemical X and the other containing Chemical Y. The tank con
Mashutka [201]
The tank with Chemical X "takes up" a space of 25ft³.  Ordinarily we think of something "taking up" space as being area or surface area; however, area is a square measurement, and this is cubic; this must be volume.  The volume of the tank with Chemical X is 1.5 times the volume of the tank containing Chemical Y; setting this up in an equation we would have
25 = 1.5<em>V</em>
We would divide both sides by 1.5 to get the volume of the tank containing Chemical Y:
\frac{25}{1.5}=\frac{1.5V}{1.5} \\16 \frac{2}{3}=V
To find the volume of a cylinder, we find the base area and multiply by the height.  We know the volume and we know the base area, so our equation to find the height of the tank containing Chemical Y would look like:
16 \frac{2}{3}=3.2h \\ 16 \frac{2}{3}=3 \frac {2}{10}h
We would now divide both sides by 3 2/10:
\frac{16 \frac{2}{3}}{3 \frac{2}{10}}= \frac{3 \frac{2}{10}h}{3 \frac{2}{10}}
This is the same as:
\frac{\frac{50}{3}}{\frac{32}{10}}=h \\ \\ \frac{50}{3}* \frac{10}{32}=h \\ \\ \frac{500}{96}
So the height of the tank containing Chemical Y is 500/96 = 5 5/24 feet.
8 0
2 years ago
In the first week of​ July, a record 1,060 people went to the local swimming pool. In the second​ week, 100 fewer people went to
vovikov84 [41]

(Can I have Brainlist?)

Answer:

10%

Step-by-step explanation:

The following information can be gotten from the question regarding the number of people that went to the swimming pool are:

First week of July = 1020

Second week = 1020 - 100 = 920

Third week = 920 + 130 = 1050

Fourth week = 1050 - 132 = 918

The percentage decrease over the four weeks will be:

= (1020 - 918)/1020 × 100

= 102/1020 × 100

= 10%

4 0
2 years ago
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