891
because 99(the greatest 2 digit number)*9(the greatest 1 digit number)=891
Answer:
X=-2 x=1 x=3 and x=-1
Step-by-step explanation:
When the problem asks you to find the zeros all they are asking for is the solution so to solve all you need to do is set each individual piece equal to zero.
Answer:
ACBD; 7
Step-by-step Explanation:
The Route Algorigtm finds the short route that is efficient, in order to find the solution following pathways.
From the pictures from the complete question,
STEP #1, there exist, three routes, which are:
AB
AC,
and AD.
*AB is not viable because of the negative distance, so it can be removed .
* the AC distance is 3,and AD distance is 8. Therefore, AC can be selected and circled.is because of AC efficiency is high compare to AD.
*from selected AC, the possible routes are ACB; 3 and ACE; 6. which are route shown in #2
* ACB is circled, because it's more shorter than ACE
*The possible routes are ACBE; 8 and ACBD; 7. which are route shown in #3 . Therefore, route ACBD is circled because it's more shorter.
From the analysis of the algorithm, the route ACBD route is the shortest and the most efficient
Answer:
3
+ 11a³ - 7a² + 18a - 18
Step-by-step explanation:
<u>When multiplying with two brackets, you need to multiply the three terms, (a²), (4a) and (-6) from the first bracket to all the terms in the second brackets, (3a²), (-a) and (3) individually. I have put each multiplied term in a bracket so it is easier.</u>
(a² + 4a - 6) × (3a² - a + 3) =
(a² × <em>3a²</em>) + {a² × <em>(-a)</em>} + (a² × <em>3</em>) + (4a × <em>3a²</em>) + {4a × <em>(-a)</em>} + (4a × <em>3</em>) + {(-6) × <em>a²</em>) + {(-6) × <em>(-a)</em>} + {(-6) × <em>3</em>}
<u>Now we can evaluate the terms in the brackets. </u>
(a² × 3a²) + {a² × (-a)} + (a² × 3) + (4a × 3a²) + {4a × (-a)} + (4a × 3) + {(-6) × a²) + {(-6) × (-a)} + {(-6) × 3} =
3 + (-a³) + 3a² + 12a³ + (-4a²) + 12a + (-6a²) + 6a + (-18)
<u>We can open the brackets now. One plus and one minus makes a minus. </u>
3 + (-a³) + 3a² + 12a³ + (-4a²) + 12a + (-6a²) + 6a + (-18) =
3 -a³ + 3a² + 12a³ -4a² + 12a -6a² + 6a -18
<u>Evaluate like terms.</u>
3 -a³ + 3a² + 12a³ -4a² + 12a -6a² + 6a -18 = 3 + 11a³ - 7a² + 18a - 18
P would equal negative three.
