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gayaneshka [121]

3 years ago

8

1) Given the following problem: I am thinking of a number. If you double the number and add 10, the result is 22.

2 answers:

professor190 [17]3 years ago

7 0

Answer:

The answer is 6

Step-by-step explanation:

What wanna start out with finding the difference by subtracting 10 from 22. This would give you the difference of 12. Since its 'double the number', we are going to find the quotient of 12 / 2 = 6. You will then end up with the answer 6.

frez [133]3 years ago

4 0

Answer:

the number is (((6))))

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Can a triangle have sides with the given lengths? Explain.

Amiraneli [1.4K]

Answer:

Option A.

Step-by-step explanation:

12 cm, 17cm, 25 cm

7 0

2 years ago

From first principle find the derivative of logx

Archy [21]

Hello!

$\large\boxed{\frac{dy}{dx}logx = \frac{1}{xln10} }$

Recall that:

$logx$ can be rewritten as:

$log_{10}x$

Use the equation for the derivative of a log expression:

$\frac{dy}{dx}log_{a}u = \frac{1}{ulna} * u'$

Substitute in the values in the expression:

$logx = \frac{1}{xln10} * 1 = \frac{1}{xln10}$

4 0

3 years ago

Identify a and b in the binomial expression (2x3 + 3y2)7.

Shkiper50 [21]

$\text{Hey there!}$

$\text{Distribute the value of 7 in each of your terms}$

$\text{(2x}^3+\text{3y}^2)(7)$

$\text{2x}^3\times7=\text{14x}^3$

$\text{3y}^2\times7=\text{21y}^2$

$\text{We cannot combine like terms because they AREN'T any in this equation}$

$\boxed{\boxed{\bf{Answer:14x^3+21y^2}}}\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{LoveYourselfFirst:)}$

8 0

3 years ago

Read 2 more answers

If cos() = − 2 3 and is in Quadrant III, find tan() cot() + csc(). Incorrect: Your answer is incorrect.

nydimaria [60]

Answer:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

Step-by-step explanation:

Given

$\cos(\theta) = -\frac{2}{3}$

$\theta \to$ Quadrant III

Required

Determine $\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

We have:

$\cos(\theta) = -\frac{2}{3}$

We know that:

$\sin^2(\theta) + \cos^2(\theta) = 1$

This gives:

$\sin^2(\theta) + (-\frac{2}{3})^2 = 1$

$\sin^2(\theta) + (\frac{4}{9}) = 1$

Collect like terms

$\sin^2(\theta) = 1 - \frac{4}{9}$

Take LCM and solve

$\sin^2(\theta) = \frac{9 -4}{9}$

$\sin^2(\theta) = \frac{5}{9}$

Take the square roots of both sides

$\sin(\theta) = \±\frac{\sqrt 5}{3}$

Sin is negative in quadrant III. So:

$\sin(\theta) = -\frac{\sqrt 5}{3}$

Calculate $\csc(\theta)$

$\csc(\theta) = \frac{1}{\sin(\theta)}$

We have: $\sin(\theta) = -\frac{\sqrt 5}{3}$

So:

$\csc(\theta) = \frac{1}{-\frac{\sqrt 5}{3}}$

$\csc(\theta) = \frac{-3}{\sqrt 5}$

Rationalize

$\csc(\theta) = \frac{-3}{\sqrt 5}*\frac{\sqrt 5}{\sqrt 5}$

$\csc(\theta) = \frac{-3\sqrt 5}{5}$

So, we have:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \tan(\theta) \cdot \frac{1}{\tan(\theta)} + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 + \csc(\theta)$

Substitute: $\csc(\theta) = \frac{-3\sqrt 5}{5}$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 -\frac{3\sqrt 5}{5}$

Take LCM

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

6 0

3 years ago

Yvette uses 6 games of tea leaves to make 24

ruslelena [56]

Answer:

Therefore last week Yvette used 72 grams of tea leaves to make 288 ounces of tea.

Step-by-step explanation:

i) 6 grams of tea leaves are used to make 24 ounces of tea.

ii) 1 gram of tea leaves can be used to make $= \frac{24}{6} = 4\hspace{0.1cm}ounces\hspace{0.1cm}of\hspace{0.1cm}tea$

iii) number of grams of tea leaves to make 288 ounces of tea

$= \frac{288}{4} = 72\hspace{0.1cm}grams\hspace{0.1cm}of\hspace{0.1cm}tea\hspace{0.1cm}leaves$

The answer is 72 grams of tea leaves are required to make 288 ounces of tea.

Therefore last week Yvette used 72 grams of tea leaves to make 288 ounces of tea.

8 0

3 years ago