Answer:
87.5 mi/hr
Explanation:
Because a = Δv / Δt (a = vf - vi/ Δt), we need to find the acceleration first to know the change in velocity so we can determine the final velocity.
vf = 60 mi/hr
vi = 0 mi/hr
Δt = 8 secs
a = vf - vi/ Δt
= 60 mi/hr - 0 mi/hr/ 8 secs
= 60 mi/hr / 8 secs
= 7.5 mi/hr^2
Now that we know the acceleration of the car is 7. 5 mi/hr^2, we can substitute it in the acceleration formula to find the final velocity when the initial velocity is 50 mi/hr after 5 secs.
vi = 50 mi/ hr
Δt = 5 secs
a = 7.5 mi/ hr^2
a = vf - vi/ Δt
7.5 = vf - 50 mi/hr / 5 secs
37.5 = vf - 50
87.5 mi/ hr = vf
Answer:
When pH = pKa, the ionizable compound in question (either acid or base) will be half protonated and half deprotonated
Explanation:
A convenient way of expressing the relative strength of an acid is by the value of its pKa, which makes it easy to see in small changes in pKa the changes associated with large variations in Ka. Small pKa values are equivalent to large Ka (dissociation constant) values, and as pKa decreases, the strength of the acid increases.
An acid will be stronger the lower its pKa and in a base it happens the other way around, which is stronger the higher its pKa.
Those dissociation constants are not fixed, they depend on other variables. For example, the dissociation constant changes at different temperatures. However, it maintains its value at the same temperature, before changes in the concentration of any of the species or even under the action of a catalyst.
In electroplating with silver, silver cyanide is used in the electrolyte rather than other compounds of silver such as silver nitrate, AgNO3, because the cyanide ion, CN-, reacts with silver ion, Ag+, to form the complex ion Ag(CN) -.
Answer:
number 3 is balanced
Explanation:
left side equal right side
D. The final substance in Beaker A is a mixture and in Beaker B is a pure substance.
