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iVinArrow [24]
3 years ago
3

Suzanne created a circuit with a battery, some copper wire, and a light bulb. How might adding a piece of gold wire to the circu

it affect the flow of electricity through the circuit? A. Gold wire will not allow the electricity to flow down the wire. B. Gold wire will allow the electricity to flow down the wire. C. Gold wire will act as a switch to turn on the circuit. D. Gold wire will act as a switch to turn off the circuit.
Chemistry
2 answers:
algol133 years ago
8 0
Because gold is a metal and a decent conductor, B is correct. It could easily bring the energy from place to place.
Citrus2011 [14]3 years ago
5 0
I'm in an engineering middle school so we learned this a long time ago. The answer is B. Because gold is a conductor of electricity (though it is not the strongest), it would allow electricity to flow through the circuit.
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If a car can go from 0 to 60 mi/hr in 8.0 seconds, what would be its final speed after 5.0 seconds if its starting speed were 50
tangare [24]

Answer:

87.5 mi/hr

Explanation:

Because a = Δv / Δt (a = vf - vi/ Δt), we need to find the acceleration first to know the change in velocity so we can determine the final velocity.

vf = 60 mi/hr

vi = 0 mi/hr

Δt = 8 secs

a = vf - vi/ Δt

= 60 mi/hr - 0 mi/hr/ 8 secs

= 60 mi/hr / 8 secs

= 7.5 mi/hr^2

Now that we know the acceleration of the car is 7. 5 mi/hr^2, we can substitute it in the acceleration formula to find the final velocity when the initial velocity is 50 mi/hr after 5 secs.

vi = 50 mi/ hr

Δt = 5 secs

a = 7.5 mi/ hr^2

a = vf - vi/ Δt

7.5 = vf - 50 mi/hr / 5 secs

37.5 = vf - 50

87.5 mi/ hr = vf

7 0
4 years ago
The pKa for a weak acid to be used in the buffer should be as close as possible to the desired pH. What if the pKa is not close
nikdorinn [45]

Answer:

When pH = pKa, the ionizable compound in question (either acid or base) will be half protonated and half deprotonated

Explanation:

A convenient way of expressing the relative strength of an acid is by the value of its pKa, which makes it easy to see in small changes in pKa the changes associated with large variations in Ka. Small pKa values are equivalent to large Ka (dissociation constant) values, and as pKa decreases, the strength of the acid increases.

An acid will be stronger the lower its pKa and in a base it happens the other way around, which is stronger the higher its pKa.

Those dissociation constants are not fixed, they depend on other variables. For example, the dissociation constant changes at different temperatures. However, it maintains its value at the same temperature, before changes in the concentration of any of the species or even under the action of a catalyst.

3 0
4 years ago
Suggest a suitable electrolyte that could be used if the iron ring is to be plated with silver​
sasho [114]
In electroplating with silver, silver cyanide is used in the electrolyte rather than other compounds of silver such as silver nitrate, AgNO3, because the cyanide ion, CN-, reacts with silver ion, Ag+, to form the complex ion Ag(CN) -.
5 0
3 years ago
Which of the following is a balanced chemical equation?
guapka [62]

Answer:

number 3 is balanced

Explanation:

left side equal right side

7 0
3 years ago
*WILL GIVE BRAINLIEST IF SOMEONE ANSWERS THIS CORRECTLY ASAP!!!!*
My name is Ann [436]

D. The final substance in Beaker A is a mixture and in Beaker B is a pure substance.

8 0
3 years ago
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