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harina [27]
3 years ago
12

The pKa for a weak acid to be used in the buffer should be as close as possible to the desired pH. What if the pKa is not close

to the desired pH? What is the problem with choosing such a weak acid used in the buffer?
Chemistry
1 answer:
nikdorinn [45]3 years ago
3 0

Answer:

When pH = pKa, the ionizable compound in question (either acid or base) will be half protonated and half deprotonated

Explanation:

A convenient way of expressing the relative strength of an acid is by the value of its pKa, which makes it easy to see in small changes in pKa the changes associated with large variations in Ka. Small pKa values are equivalent to large Ka (dissociation constant) values, and as pKa decreases, the strength of the acid increases.

An acid will be stronger the lower its pKa and in a base it happens the other way around, which is stronger the higher its pKa.

Those dissociation constants are not fixed, they depend on other variables. For example, the dissociation constant changes at different temperatures. However, it maintains its value at the same temperature, before changes in the concentration of any of the species or even under the action of a catalyst.

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Element c has a strong emmission aound 450nm Does this emmission line reprosent a lower of higher emergy line at 627 nm?
Julli [10]

It  respresents the higher energy level than 627nm .

<h3>What is a emission line ? </h3>

Emission lines are the glowing hot gas emits lines of light whereas absorption line  refers to the tendency of  cool atmospheric gas to absorb the same line of light.Some lights produce dark band when the light passes through gas in the atmosphere . There are two line spectrum  and absorption.

 spectrum is an excitement of  electrons from lower to higher energy levels and when it comes back it releases energy in the terms of colourful lights .

It represents the  higher energy levels than 627nm because Energy is inversly proportional to wavelength .

to learn more about Emission lines click here

 brainly.com/question/28184999

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5 0
2 years ago
The product side of a chemical reaction is shown.
Inga [223]

The number that represents the coefficient on the product side of the chemical reaction, -- > 7Ti_2(SO_4)_3 is 7.

<h3>Coefficients of chemical equations</h3>

In equations representing chemical reactions, the coefficient of each reactant or product of a reaction is the number that comes on the left-hand side just before the chemical formula.

The coefficient of each species in a chemical reaction is obtainable when the equation of the reaction is balanced.

For example, in the following equation: 2A + B = 3C + D

The coefficients of A, B, C, and D are 2, 1, 3, and 1 respectively.

Applying this to the product side of a chemical reaction;  -- > 7Ti_2(SO_4)_3

It means that the coefficient of the product is 7.

More on coefficients of chemical equations can be found here: brainly.com/question/28294176

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7 0
1 year ago
HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
Trava [24]

Answer:

b..................

4 0
3 years ago
Read 2 more answers
g Calculate the pOH of a solution that results from mixing 23.3 mL of 0.16 M trimethylamine ((CH3)3N) with 44.1 mL of 0.15 M (CH
hichkok12 [17]

Answer:

pOH = 5.961

Explanation:

To find the pH of a weak base we can use Henderson-Hasselbalch equation for weak bases:

pOH = pKb + log [(CH₃)₃NHCl] / [(CH₃)₃N]

<em>Where pKb is -log Kb = 4.187 and [] could be taken as moles of each specie.</em>

<em />

<em>Moles (CH₃)₃NHCl:</em>

0.0441L * (0.15mol/L) = 6.615x10⁻³moles

<em>Moles (CH₃)₃N:</em>

0.0233L * (0.16mol/L) = 3.728x10⁻³moles

And pOH is:

pOH = pKb + log [(CH₃)₃NHCl] / [(CH₃)₃N]

pOH = 4.187 + log [6.615x10⁻³moles] / [3.728x10⁻³moles]

<h3>pOH = 5.961</h3>

<em />

6 0
3 years ago
How many moles of I(iodine)2 are there in a 500.0g bottle? Please include significant figures
dolphi86 [110]

Answer:

Number of moles = 1.97 mol

Explanation:

Given data;

Number of moles of I₂ = ?

Mass = 500.0 g

Solution:

Number of moles = mass/ molar mass

Molar mass of  I₂ = 253.8 g/mol

Number of moles = 500 g / 253.8 g/mol

Number of moles = 1.97 mol

4 0
3 years ago
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