From the ideal gas law, PV = nRT, we can rearrange the equation to solve for T given the other parameters.
T = PV/nR
where P = 0.878 atm, V = 1.20 L, n = 0.0470 moles, and R = 0.082057 L•atm/mol•K. Plugging in our values, we obtain the temperature in Kelvin:
T = (0.878 atm)(1.20 L)/(0.0470 mol)(0.082057 L•atm/mol•K)
T = 273 K
So, the second answer choice would be correct.
At present, most of the energy used in the united states is supplied by:
<span>Fossil fuels.
I hope this help!
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Answer:
Another name of activation energy is "Needed energy" .
Explanation:
Activation energy can be imagined of as the measurement of the potential barrier (seldom described the energy barrier) distributing minima of the potential energy surface concerning the initial and ultimate thermodynamic phase. For a chemical reaction or distribution to advance at a reasonable rate, the specific temperature of the operation should be high satisfactory so that there subsists an apparent number of particles with translational energy equivalent to or higher than the activation energy. The word Activation Energy was founded in 1889 by the Swedish expert Svante Arrhenius.
Hello!
So, we are given a ball with a density of 1100 kg/m³, and two liquids: water (1000 kg/m³) and honey (1400 kg/m³). Our goal is to determine if the ball will sink or float in the given liquids.
Let's take two common substances: water and ice. Water has a density of 1000 kg/m³ and ice has a density of about 917 kg/m³. You would notice that the ice is always floating when you put ice and water together. This would occur if you have other substances.
Here's what you should know:
- If the density of an object is greater than the liquid it is in, then that object will sink.
- If the density of an object is less than the liquid it is in, then that object will float.
Since the ball has a density of 1100 kg/m³, and water's density is 1000 kg/m³, then the ball will sink. If the ball is placed in honey, then it will float because the density of honey (1400 kg/m³) is greater than the ball's density.
Therefore, objects with a greater density than the surrounding liquid sink, while objects with a smaller density than the surrounding liquid float, which is the fourth choice.
Answer:
Examples of ROS include peroxides, superoxide, hydroxyl radical, singlet oxygen, and alpha-oxygen.