Answer:
Spring summer fall.
Explanation:
As a general rule, if you're in the Northern Hemisphere, look towards the southern skies to see the galactic core. This can be southeast (Spring), due south (Summer), or southwest (Fall) depending on the time of year. As mentioned above, Sagittarius is found nearest the galactic core.
Answer:
The answer is 380.
Explanation:
Significant figures:
All non-zero digits are consider significant figures like 1, 2, 3, 4, 5, 6, 7, 8, 9.
Leading zeros are not consider as a significant figures. e.g. 0.06 in this number only one significant figure present which is 6.
Zero between the non zero digits is consider significant like 108 consist of three significant figures.
The zeros at the right side e.g 6300 are also significant. There are four significant figures are present.
How to round the value to three significant figures.
First of all we will place the vertical line after 3rd digit.
379/5
Now we will look at the 4th digit. If it is five or more than five then one is added to 3rd digit. If it is less than five the 3rd digit remain same. In given value 4th digit is 5 thus one is added into 9 and the value become 380.
The answer is 380.
When a plant goes through photosynthesis, it uses light energy and converts it into chemical energy
Answer:
gain or loses electrons.
Explanation:
Because the atom need to be balanced.
<span>Reaction: CI2 + H2O ----> HCIO + HCI
Oxidations states:
The oxitation state of Cl2 = 0, because the oxidation state of an atom alone or a molucule with one kind of atom is always 0.
The
oxidation state of Cl in HClO is +1 because the oxidation state of H is
+ 1, the oxidation state of O is - 2, and the molecule is neutral, so
+1 + 1 - 2 = 0
The oxidation state of Cl in HCl is - 1, because the oxidation state of H is +1 and the molecule is neutral, so - 1 + 1 = 0.
Also,
you shall remember that when an atom increases its oxidation state is
is oxidized and when an atoms reduces its oxidations state it is
reduced.
With that you conclude that the right option is the last statement: </span>Cl
has an oxidation number of 0 in Cl2. It is then reduced to CI- with an
oxidation number of –1 in HCl and is oxidized to Cl+ with an oxidation
number +1 in HClO.
