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eduard
3 years ago
15

If a car can go from 0 to 60 mi/hr in 8.0 seconds, what would be its final speed after 5.0 seconds if its starting speed were 50

mi/hr?
a=
vf=
vi=
t=
Chemistry
1 answer:
tangare [24]3 years ago
7 0

Answer:

87.5 mi/hr

Explanation:

Because a = Δv / Δt (a = vf - vi/ Δt), we need to find the acceleration first to know the change in velocity so we can determine the final velocity.

vf = 60 mi/hr

vi = 0 mi/hr

Δt = 8 secs

a = vf - vi/ Δt

= 60 mi/hr - 0 mi/hr/ 8 secs

= 60 mi/hr / 8 secs

= 7.5 mi/hr^2

Now that we know the acceleration of the car is 7. 5 mi/hr^2, we can substitute it in the acceleration formula to find the final velocity when the initial velocity is 50 mi/hr after 5 secs.

vi = 50 mi/ hr

Δt = 5 secs

a = 7.5 mi/ hr^2

a = vf - vi/ Δt

7.5 = vf - 50 mi/hr / 5 secs

37.5 = vf - 50

87.5 mi/ hr = vf

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How many milliliters are in 425 g of bromine if the density of bromine is 3.12 g/cm3
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Students in a chemistry class added 5 g of Zinc to 50 g of hydrochloric acid. A chemical reaction occurred that produced zinc ch
Vinil7 [7]

Answer:

Mass = 11 g

Explanation:

Given data:

Mass of Zn = 5 g

Mass of HCl = 50 g

Mass of hydrogen gas produced = 6 g

Mass of zinc chloride produced = ?

Solution:

Chemical equation:

Zn + 2HCl    →   ZnCl₂ + H₂

Number of moles of Zn:

Number of moles = mass / molar mass

Number of moles = 5 g / 65.38 g/mol

Number of moles = 0.08 mol

Number of moles of HCl :

Number of moles = mass / molar mass

Number of moles = 50 g / 36.5 g/mol

Number of moles = 1.4 mol

Now we will compare the moles of both reactant with zinc chloride.

              Zn           :           ZnCl₂

               1             :             1

              0.08       :        0.08

            HCl          :         ZnCl₂

              2            :           1

             1.4          :         1/2×1.4 =0.7 mol

The number of moles of zinc chloride produced by Zn are less so it will limiting reactant.

Mass of zinc chloride:

Mass = number of moles × molar mass

Mass = 0.08 mol × 136.3 g/mol

Mass = 11 g

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