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Oh please first if the rectangle was compete, it's area would be 8.
The area of the missing triangle is =2.
8-2=6<u> </u>
<u>And there you go! Your answer is 6.</u>
Answer:
QR is tangent to circle P at point Q
=> RQP = 90 deg
=> RQP is right triangle.
=> Applying Pythagorean theorem for right triangle RQP:
QP^2 + QR^2 = RP^2
=>4^2 + QR^2 = RP^2
=> Option A is correct.
(4^2 + (4*)^2 = 16 + 48 = 64 = 8^2)
=> Option C is correct.
(4^2 + 3^2 = 16 + 9 = 25 = 5^2)
=> Option D is correct
(4^2 + 2^2 = 16 + 4 = 20 = (2)^2)
Hope this helps!
:)