Find the area of an equilateral triangle (regular 3-gon) with the given measurement. 6-inch radius A = sq. in.

1 answer:

8 0

$\bf \textit{area of an equilateral triangle}\\\\
A=\cfrac{s^2\sqrt{3}}{4}\qquad 
\begin{cases}
s=length~of\\
\qquad a~side\\
-------\\
s=6
\end{cases}\implies A=\cfrac{6^2\sqrt{3}}{4}\implies A=\cfrac{36\sqrt{3}}{4}
\\\\\\
A=9\sqrt{3}$

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