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tekilochka [14]
3 years ago
8

Write an equation in point-slope form that has a y-intercept at (0, 12) and also contains the point (1,2)

Mathematics
1 answer:
harkovskaia [24]3 years ago
6 0

Answer:

y-2=-10(x-1).

Step-by-step explanation:

The point slope form is y-y_1 = m(x-x_1). Now we find the slope, which is 2-12 (-10)/1-0(1). This gives us -10. Now we plug the coordinates from one of the points and the slope to get y-2=-10(x-1).

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I'm confused in this question. Could anyone help me please?
stepladder [879]

Answer:

I think answer is opction no. 2

Step-by-step explanation:

x = C - 5/2

3 0
3 years ago
Evaluate the dot product of (2,4) and (1,2)
Aleksandr [31]

ANSWER

The dot product is 10.

EXPLANATION

The given vectors are (2,4) and (1,2).

If we have the vectors

u=(a,b) and v=(c,d)

Then the dot product of the two vectors is given by

u \bullet \: v = ac + bd

This implies that,

(2,4)  \bullet(1,2) = 2 \times 1 + 4 \times 2

This simplifies to;

(2,4)  \bullet(1,2) = 2  + 8 = 10

4 0
3 years ago
Slope and the intercept
Pie

Answer:

y-intercept: (0, 3) slope: 3

Step-by-step explanation:

7 0
3 years ago
30 points plz help<br> Use the draggable points to graph the equation<br> 1<br> y=<br> 2x+3
Nikitich [7]

Answer:

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3 0
3 years ago
Why is the answer A ?<br>why can't D work?
attashe74 [19]
The negative in a = -2 for answer A represents a reflection over the x-axis.
What does the cosine graph usually look like?.....It goes through point (0,1) and decreases.
The graph shown goes through point (0,-2). Since there are no vertical or horizontal shifts, the graph has an amplitude of 2 and reflects over the x-axis.

a=2 for answer D does not represent the reflection over the x-axis.


7 0
3 years ago
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