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Dmitry [639]
4 years ago
10

T times 3/4 for t =8/9

Mathematics
1 answer:
denis-greek [22]4 years ago
6 0
Because T = 8/9, 3/4 • T is 3/4 • 8/9 = 2/3
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Given that ∠STV = 108° and ∠RST = 50°, determine the missing angles:
Mekhanik [1.2K]
A. 108 degrees
b. 72 degrees
c. 108 degrees

Hope this helps :)
7 0
2 years ago
Write the standard equation for the circle 30. Center (2,7), r=4. 31. Center (-6,-8), that passes treough (0,0)
Salsk061 [2.6K]
The standard equation of the circle is:

(x-h)^2+(y-k)^2=r^2 where (h,k) it the center of the circle and r is the radius...

so

30.

(x-2)^2+(y-7)^2=16

31.

We need to find the radius...(I'll just use the Pythagorean Theorem)

r^2=6^2+8^2

r^2=36+64

r^2=100  (so the radius is 10) and its center is (-6,-8) so

(x+6)^2+(y+8)^2=100
3 0
4 years ago
At a college production of a​ play, 300300 tickets were sold. the ticket prices were​ $8, $10, and​ $12, and the total income fr
Montano1993 [528]
(8t + 10t) + 55*12t= 300300

18t + 660t = 300300

t = 442.920354

time that number by each ticket type( do not round up). That'll give you each type of tickets sold.

8*442.920354 = 3543.36283

10*442.920354 = 4429.20354

55 *(12*442.920354) = 292327.434

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3 0
3 years ago
Find the least common denominator of 3/8 and 11/2​
Elden [556K]

Answer:

8

Step-by-step explanation:

Note that 2 divides into 8 evenly, yielding the quotient 4.  8 is the LCD.  To combine 3/8 and 11/2, we would rewrite 11/2 as

4·11

------ = 44/8

 4·2

and then combine 44/8 with 3/8.  The sum would be 47/8.

In summary, the LCD of 3/8 and 11/2 is 8; 3/8 stays as is and 11/2 is rewritten by mult. numerator and denominator by 4 each.

4 0
3 years ago
What is the resistance of a 1.00X10^2 -Ω , a 2.50-kΩ , and a 4.00-k Ω resistor connected in parallel?
Andreas93 [3]

Answer:

Therefore, the total Resistance:  R = 93.9 Ω

Step-by-step explanation:

Given

R₁ = 1 × 10²

R₂ = 2.5 kΩ = 2.5 × 10³ Ω

R₃ = 4  kΩ = 4 × 10³ Ω

Given that the given resisters are connected parallel, so using the formula to calculate the total Resistance R:

\frac{1}{R}\:=\:\frac{1}{R_1}\:+\:\frac{1}{R_2}+\frac{1}{R_3}

susbtituting R₁ = 1 × 10², R₂ = 2.5 × 10³ Ω, and R₃ = 4 × 10³ Ω

\frac{1}{R}=\frac{1}{1\times \:10^2}+\frac{1}{2.5\times \:10^3}+\frac{1}{4\times \:10^3}

Multiply by LCM of R, 100, 2500, and 4000:   20000 R

\frac{1}{R}\cdot \:20000R=\frac{1}{1\cdot \:10^2}\cdot \:20000R+\frac{1}{2.5\cdot \:10^3}\cdot \:20000R+\frac{1}{4\cdot \:10^3}\cdot \:20000R

simplify

20000=213R

Switch sides

213R=20000

Divide both sides by 213

\frac{213R}{213}=\frac{20000}{213}

Simplify

R=\frac{20000}{213}

R = 93.9 Ω

Therefore, the total Resistance:  R = 93.9 Ω

4 0
3 years ago
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