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3 years ago

Alexander is riding his bicycle to school. After one mile he is a third of the way there. How much more does he have to ride

Mathematics

2 answers:

natulia [17]3 years ago

7 0

If the question unit is miles, then he has 2 miles to go, the trip total is 3 miles.

bogdanovich [222]3 years ago

7 0

You are given
1 mile = (1/3)*(distance to school)
Multiply this equation by 3 and you have
3 mile = (distance to school)

You also know that
(distance ridden so far) +(remaining distance) = (distance to school)
Subsituting given information, this is
1 mile + (remaining distance) = 3 mile
Subtracting 1 mile from this equation gives
(remaining distance) = 2 miles

Alexander has 2 miles more to ride.

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If the product of the integers a, b, and c is 1, then what is the difference between the largest and the smallest possible

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Since there are no multiples other than 1 and -1 that could multiply in any way to equal 1, those are the only numbers you can really work with

it is a possibility that a, b, and c could equal 1 but then it would go wrong when comes time to subtract since all numbers are equal and cannot subtract largest from smallest.

a logical approach would be to try -1, -1, and 1 since -1 * -1 = 1 and then 1* 1 =1

we can make a= -1 , b= -1, and c= 1
(we need b to equal -1 so that we get an answer of -1 opposed to if we made a=-1 and c=-1, all outcomes would equal 1)
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since 1 is the largest possible outcome and -1 is the lowest possible outcome you should subtract the two

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The answer should be D: 2

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Answer:

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Read 2 more answers

When Alice spends the day with the babysitter, there is a 0.6 probability that she turns on the TV and watches a show. Her littl

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Answer:

a) There is a 48% probability that both Alice and Betty watch TV tomorrow.

b) There is a 48% probability that Betty watches TV tomorrow.

c) There is a 12% probability that only Alice watches TV tomorrow.

Step-by-step explanation:

We have these following probabilities:

A 60% probability that Alice watches TV.

If Alice watches TV, an 80% probability Betty watches TV.

If Alice does not watch TV, a 0% probability that Betty watches TV, since she cannot turn the TV on by herself.

a) What is the probability that both Alice and Betty watch TV tomorrow?

Alice watches 60% of the time. Betty watches in 80% of the time Alice watches. So:

$P = 0.6*0.8 = 0.48$

There is a 48% probability that both Alice and Betty watch TV tomorrow.

b) What is the probability that Betty watches TV tomorrow?

Since Betty only watches when Alice watches(80% of the time), this probability is the same as the probability of both of them watching. So

$P = 0.6*0.8 = 0.48$

There is a 48% probability that Betty watches TV tomorrow.

c) What is the probability that only Alice watches TV tomorrow?

There is a 60% probability that Alice watches TV tomorrow. If she watches, there is an 80% probability that Betty watches and a 20% probability she does not watch.

$P = 0.6*0.2 = 0.12$

There is a 12% probability that only Alice watches TV tomorrow.

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